java – 从任何给定的日期间隔返回一周的1到7天

发布时间：2020-12-15 04:32:20 所属栏目：Java 来源：网络整理

导读：我想从日期间隔返回一张日期地图： 1至7天： From: "2016-02-09" to To: "2016-02-09" - return : Tue From: "2016-02-09" to To: "2016-02-12" - return : Tue,Wed,Thu,Fri From: "2016-02-02" to To: "2016-04-12" - return : Tue,Fri,Sat,Sun,Mon (this s

我想从日期间隔返回一张日期地图：

> 1至7天：

From: "2016-02-09" to To: "2016-02-09" -> return : Tue
     From: "2016-02-09" to To: "2016-02-12" -> return : Tue,Wed,Thu,Fri
     From: "2016-02-02" to To: "2016-04-12" -> return : Tue,Fri,Sat,Sun,Mon (this should be sorted from Monday for the map)

>排序的地图(周从星期一开始),返回的日期为关键字符串(字符串),值为always = true(布尔值),将重新用于其他目的.

我想使用joda-time 2.8.1,但我不知道如何处理日期间隔？
我设法得到我想要的部分,但只有一天：

String input = "2016-02-09";
DateTimeFormatter formatter = DateTimeFormat.forPattern( "yyyy-MM-dd" );
LocalDate localDate = formatter.parseLocalDate( input );
Locale locale = Locale.US;
DateTimeFormatter formatterOutput = DateTimeFormat.forPattern( "E" ).withLocale( locale );
String output = formatterOutput.print( localDate ); //Result = Tue

解决方法

Joda-Time不支持(关闭)日历日期的间隔,而只支持瞬间的间隔.所以这里有一个特别的解决方法：

LocalDate start = LocalDate.parse("2016-02-09");
LocalDate end = LocalDate.parse("2016-02-12");
if (start.isAfter(end))  {
    return Collections.emptyMap();
}

LocalDate current = start;
Map<Integer,Boolean> map = new TreeMap<>();

do {
    map.put(current.getDayOfWeek(),Boolean.TRUE);
    current = current.plusDays(1);
} while (!current.isAfter(end) && map.size() < 7);

LocalDate ref = new LocalDate(2016,2,7); // sunday
DateTimeFormatter f = DateTimeFormat.forPattern("E").withLocale(Locale.US);
StringBuilder sb = new StringBuilder();

for (int dayOfWeek : map.keySet()) {
    String output = f.print(ref.plusDays(dayOfWeek));
    sb.append(",");
    sb.append(output);
}
System.out.println(sb.delete(0,2).insert(0,"[").append(']').toString());
// [Tue,Fri]
return map;

（编辑：李大同）

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