Java 8,Lambda:在分组列表中排序并将所有组合并到列表中
发布时间:2020-12-15 02:55:53 所属栏目:Java 来源:网络整理
导读:基于以下答案: https://stackoverflow.com/a/30202075/8760211 如何通过stud_id对每个组进行排序,然后通过stud_location返回一个包含所有学生的List作为分组的结果,然后按stud_id排序? 将它作为现有Lambda表达式的扩展会很棒: MapString,ListStudent stud
基于以下答案:
https://stackoverflow.com/a/30202075/8760211
如何通过stud_id对每个组进行排序,然后通过stud_location返回一个包含所有学生的List作为分组的结果,然后按stud_id排序? 将它作为现有Lambda表达式的扩展会很棒: Map<String,List<Student>> studlistGrouped = studlist.stream().collect(Collectors.groupingBy(w -> w.stud_location)); 我需要基于原始列表中元素的顺序进行分组. First group: "New York" Second group: "California" Third group: "Los Angeles" 1726,"John","New York" 4321,"Max","California" 2234,"Andrew","Los Angeles" 5223,"Michael","New York" 7765,"Sam","California" 3442,"Mark","New York" 结果将如下所示: List<Student> groupedAndSorted = .... 1726,"New York" 3442,"New York" 5223,"New York" 4321,"California" 7765,"California" 2234,"Los Angeles" 我尝试过以下方法: studlistGrouped.entrySet().stream().sorted(Comparator.compar??ing(Map.Entry::getVa??lue)) 但这不起作用. 解决方法
如果我找对你,你需要一个List< Student> (不是地图)学生按其位置分组,并按组内的ID排序,组中的组也按ID排序,而不是按位置名称排序.这是可能的,但需要一个分组和两个排序:
//first,use your function to group students Map<String,List<Student>> studlistGrouped = students.stream() .collect(Collectors.groupingBy(Student::getLocation,Collectors.toList())); //then sort groups by minimum id in each of them List<Student> sorted = studlistGrouped.entrySet().stream() .sorted(Comparator.comparing(e -> e.getValue().stream().map(Student::getId).min(Comparator.naturalOrder()).orElse(0))) //and also sort each group before collecting them in one list .flatMap(e -> e.getValue().stream().sorted(Comparator.comparing(Student::getId))).collect(Collectors.toList()); 这将产生以下结果: Student{id='1726',name='John',location='New York'} Student{id='3442',name='Mark',location='New York'} Student{id='5223',name='Michael',location='New York'} Student{id='2234',name='Andrew',location='Los Angeles'} Student{id='4321',name='Max',location='California'} Student{id='7765',name='Sam',location='California'} 也许这可以更优雅地完成,欢迎提出建议 编辑:在写这个答案的时候,没有提到基于OPs问题中原始列表中元素顺序的分组.所以我的假设是按ID分类列表和组.对于基于原始列表中的顺序的解决方案,请参阅其他答案,例如,Holgers one (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |