java – 密码包含@时,“期望/遵循URI中的主机名”异常
发布时间:2020-12-15 02:48:14 所属栏目:Java 来源:网络整理
导读:我正在尝试将本地系统文件复制到服务器 package classes;import java.io.File;import java.io.FileInputStream;import java.io.InputStream;import java.util.Properties;import org.apache.commons.vfs.FileObject;import org.apache.commons.vfs.FileSyste
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我正在尝试将本地系统文件复制到服务器
package classes;
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStream;
import java.util.Properties;
import org.apache.commons.vfs.FileObject;
import org.apache.commons.vfs.FileSystemOptions;
import org.apache.commons.vfs.Selectors;
import org.apache.commons.vfs.impl.StandardFileSystemManager;
import org.apache.commons.vfs.provider.sftp.SftpFileSystemConfigBuilder;
public class SendMyFiles {
public static void main(String[] args) {
SendMyFiles sendMyFiles = new SendMyFiles();
String fileToFTP = "zcol_30092013.xls";
sendMyFiles.startFTP(fileToFTP);
}
public boolean startFTP(String fileToFTP){
Properties prop = new Properties();
InputStream in = getClass().getResourceAsStream("/config.properties");
StandardFileSystemManager manager = new StandardFileSystemManager();
try {
prop.load(in);
String serverAddress = prop.getProperty("serverAddress").trim();
String userId = prop.getProperty("userId").trim();
String password = prop.getProperty("password").trim();
String remoteDirectory = prop.getProperty("remoteDirectory").trim();
String localDirectory = prop.getProperty("localDirectory").trim();
System.out.println("Cheking values "+serverAddress+" "+userId+" "+password+" "+remoteDirectory+" "+localDirectory);
//check if the file exists
String filepath = localDirectory;
System.out.println("filepath "+filepath);
File file = new File(filepath);
System.out.println(file+" "+file.exists());
if (!file.exists())
throw new RuntimeException("Error. Local file not found");
//Initializes the file manager
manager.init();
//Setup our SFTP configuration
FileSystemOptions opts = new FileSystemOptions();
SftpFileSystemConfigBuilder.getInstance().setStrictHostKeyChecking(
opts,"no");
SftpFileSystemConfigBuilder.getInstance().setUserDirIsRoot(opts,true);
SftpFileSystemConfigBuilder.getInstance().setTimeout(opts,10000);
//Create the SFTP URI using the host name,userid,password,remote path and file name
String sftpUri= "sftp://" + userId + ":" + password + "@" + serverAddress + "/"
+ remoteDirectory+ fileToFTP;
// Create local file object
System.out.println("sftp uri "+sftpUri);
System.out.println(file.getAbsolutePath());
FileObject localFile = manager.resolveFile(file.getAbsolutePath());
// Create remote file object
FileObject remoteFile = manager.resolveFile(sftpUri,opts);
// Copy local file to sftp server
remoteFile.copyFrom(localFile,Selectors.SELECT_SELF);
System.out.println("File upload successful");
}
catch (Exception ex) {
ex.printStackTrace();
return false;
}
finally {
manager.close();
}
return true;
}
}
在执行以下异常的代码时: org.apache.commons.vfs.FileSystemException: Invalid absolute URI "sftp://vmsorbit:***@172.16.16.148/universe/files/zcol_30092013.xls".
at org.apache.commons.vfs.provider.AbstractOriginatingFileProvider.findFile(AbstractOriginatingFileProvider.java:62)
at org.apache.commons.vfs.impl.DefaultFileSystemManager.resolveFile(DefaultFileSystemManager.java:692)
at org.apache.commons.vfs.impl.DefaultFileSystemManager.resolveFile(DefaultFileSystemManager.java:620)
at classes.SendMyFiles.startFTP(SendMyFiles.java:67)
at classes.SendMyFiles.main(SendMyFiles.java:23)
Caused by: org.apache.commons.vfs.FileSystemException: Expecting / to follow the hostname in URI "sftp://vmsorbit:***@172.16.16.148/universe/files/zcol_30092013.xls".
at org.apache.commons.vfs.provider.HostFileNameParser.extractToPath(HostFileNameParser.java:155)
at org.apache.commons.vfs.provider.URLFileNameParser.parseUri(URLFileNameParser.java:49)
at org.apache.commons.vfs.provider.AbstractFileProvider.parseUri(AbstractFileProvider.java:188)
at org.apache.commons.vfs.provider.AbstractOriginatingFileProvider.findFile(AbstractOriginatingFileProvider.java:58)
... 4 more
在线获得错误 FileObject localFile = manager.resolveFile(file.getAbsolutePath()); 密码包含特殊字符@. 解决方法
如果您的密码包含@,则URL解析器将其视为userinfo – hostname分隔符.然后它会扫描一个主机名,在下一个@上停止,它会分隔实际的主机名.接下来,它检查主机名后面的第一个字符是/,它不是什么,因为它是@.逻辑对我来说没有多大意义,但解释了令人困惑的错误信息
但无论如何,即使逻辑更好,你的密码或用户名也不能有文字@.您必须将其URL编码为@. 如果您的用户名/密码是可变的,您应该使用 public static String encode(String decodedStr) 请注意,文档中的注释是错误的.它说方法“从字符串中删除%nn编码.”,而它实际上添加了它们. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
