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java – security-role-ref无法正常工作

发布时间:2020-12-15 02:34:52 所属栏目:Java 来源:网络整理
导读:这些是我的web.xml的内容 ?xml version="1.0" encoding="ISO-8859-1"?web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.
这些是我的web.xml的内容

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
     version="3.0" metadata-complete="true">
  <servlet>
    <security-role-ref>
      <role-name>MY_GROUP_NAME</role-name>
      <role-link>REGISTERED_USER</role-link>
    </security-role-ref>
  </servlet>
  <servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <resource-ref>
    <description>My datasource</description>
    <res-ref-name>jdbc/XXXXXXXX</res-ref-name>
    <res-type>javax.sql.DataSource</res-type>
    <res-auth>Container</res-auth>
  </resource-ref>
  <security-constraint>
    <display-name>Example Security Constraint</display-name>
    <web-resource-collection>
      <web-resource-name>Protected Area</web-resource-name>
      <!-- Define the context-relative URL(s) to be protected -->
      <url-pattern>/protected/`*`</url-pattern>
      <!-- If you list http methods,only those methods are protected -->
      <http-method>DELETE</http-method>
      <http-method>GET</http-method>
      <http-method>POST</http-method>
      <http-method>PUT</http-method>
    </web-resource-collection>
    <auth-constraint>
      <!-- Anyone with one of the listed roles may access this area -->
      <role-name>tomcat</role-name>
      <role-name>role1</role-name>
      <role-name>REGISTERED_USER</role-name>
    </auth-constraint>
  </security-constraint>
  <!-- Default login configuration uses form-based authentication -->
  <login-config>
    <auth-method>FORM</auth-method>
    <realm-name>Example Form-Based Authentication Area</realm-name>
    <form-login-config>
      <form-login-page>/protected/login.jsp</form-login-page>
      <form-error-page>/protected/error.jsp</form-error-page>
    </form-login-config>
  </login-config>
  <!-- Security roles referenced by this web application -->
  <security-role>
    <role-name>role1</role-name>
  </security-role>
  <security-role>
    <role-name>tomcat</role-name>
  </security-role>
  <security-role>
    <role-name>REGISTERED_USER</role-name>
  </security-role>
</web-app>

当我使用ldap中的组MY_GROUP_NAME中的有效用户执行登录时,request.getRemoteUser()和request.getUserPrincipal()工作正常.针对MY_GROUP_NAME测试用户

String role = request.getParameter("role"); 
request.isUserInRole(role);

工作良好.

问题是在针对role_USER角色测试用户时不起作用.有没有人看到我在这里失踪的东西?

一些额外的信息

我使用Apache Tomcat v7.0.22

LDAP是OpenDJ 2.4.5

Windows 7操作系统

解决方法

我没有使用OpenDJ,但根据 https://wikis.forgerock.org/confluence/display/OPENDJ/Configure+Apache+Tomcat+with+OpenDJ+as+an+Identity+Store tomcat角色和LDAP规则之间没有“映射”,因为映射是一对一的,名称应该是相同的. 您要使用的LDAP组应定义为Tomcat角色,您应该在Web描述符的security-role部分使用它们的名称(web.xml).

(编辑:李大同)

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