java – OpenSSL解密返回false

这是我的Java代码：

private String encryptAES(String text) throws Exception
{
    String key = "something-random";
    SecretKeySpec skeySpec = new SecretKeySpec(key.getBytes(),"AES");

    Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");

    cipher.init(Cipher.ENCRYPT_MODE,skeySpec);
    byte[] encrypted = cipher.doFinal(text.getBytes());

    String encrypttext = Base64.encodeToString(encrypted,Base64.URL_SAFE|Base64.NO_WRAP);

    Log.v("ENCRYPTED",encrypttext); // 6sAfStQJ2zNUJLdRgXZsTA==

    return encrypttext;
}

试图在PHP中解密密码：

$output = openssl_decrypt("6sAfStQJ2zNUJLdRgXZsTA==","AES-256-ECB","something-random");
var_dump($output); // bool(false)

来自openSLL的给定错误：

error:06065064:digital envelope routines:EVP_DecryptFinal_ex:bad decrypt

有谁知道什么是错的？我试图寻找错误,但一切都与node.js有关

基于@RandomSeed的回答,我将PHP代码更改为以下内容：

$output = openssl_decrypt(base64_decode("6sAfStQJ2zNUJLdRgXZsTA=="),"something-random");

这会导致错误：

error:0606506D:digital envelope routines:EVP_DecryptFinal_ex:wrong final block length

这个编辑过的解密函数也返回bool(false)