Java点与“任何字符”不匹配
发布时间:2020-12-15 02:04:20 所属栏目:Java 来源:网络整理
导读:点应匹配任何字符.那么为什么这个正则表达式不起作用呢? String url = "http://wikipedia.org";System.out.println(url.replace("htt.://","")); 输出:http://wikipedia.org 解决方法 String.replace() 编译文字正则表达式.你应该使用 String.replaceAll(
点应匹配任何字符.那么为什么这个正则表达式不起作用呢?
String url = "http://wikipedia.org"; System.out.println(url.replace("htt.://","")); 输出:http://wikipedia.org 解决方法String.replace() 编译文字正则表达式.你应该使用
String.replaceAll() 或
String.replaceFirst() :
String url = "http://wikipedia.org"; System.out.println(url.replaceFirst("htt.://","")); 这是来自Java源代码的方法.replace(): /** * Replaces each substring of this string that matches the literal target * sequence with the specified literal replacement sequence. The * replacement proceeds from the beginning of the string to the end,for * example,replacing "aa" with "b" in the string "aaa" will result in * "ba" rather than "ab". * * @param target The sequence of char values to be replaced * @param replacement The replacement sequence of char values * @return The resulting string * @throws NullPointerException if <code>target</code> or * <code>replacement</code> is <code>null</code>. * @since 1.5 */ public String replace(CharSequence target,CharSequence replacement) { return Pattern.compile(target.toString(),Pattern.LITERAL).matcher( this).replaceAll(Matcher.quoteReplacement(replacement.toString())); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |