java – 一个简单的闰年逻辑问题
发布时间:2020-12-15 02:03:55 所属栏目:Java 来源:网络整理
导读:public class LeapYear { public static void main(String[] args) { int year = Integer.parseInt(args[0]); boolean isLeapYear; // divisible by 4 isLeapYear = (year % 4 == 0); // divisible by 4 and not 100 isLeapYear = isLeapYear (year % 100 !=
public class LeapYear { public static void main(String[] args) { int year = Integer.parseInt(args[0]); boolean isLeapYear; // divisible by 4 isLeapYear = (year % 4 == 0); // divisible by 4 and not 100 isLeapYear = isLeapYear && (year % 100 != 0); // divisible by 4 and not 100 unless divisible by 400 isLeapYear = isLeapYear || (year % 400 == 0); System.out.println(isLeapYear); } } 我作为我的输入传递了1900.第一个条件评估为真,因为它可以被4整除,但1900也应该被100整除… 为什么我得到1900年不是闰年….第二个&&条件…(年%100!= 0) 更新 public class TestSample { public static void main(String[] args){ int leapYear = Integer.parseInt(args[0]); boolean isLeapYear; isLeapYear = (leapYear % 4 == 0) && (leapYear % 100 != 0); System.out.println("Its Leap Year" +isLeapYear); } } 编译这个程序打印1900不是leapYear How ????在这里,我甚至没有检查它是否可以被400整除. 解决方法
解释你的代码:
isLeapYear = (year % 4 == 0); // isLeapYear = true isLeapYear = isLeapYear && (year % 100 != 0); // year % 100 IS 0. so the second part evaluates to false giving // true && false which yields isLeapYear as false isLeapYear = isLeapYear || (year % 400 == 0); // this is just false || false // which evaluates to false 我给你的另一个建议就是使用GregorianCalendar找到你想要的东西: GregorianCalendar cal = new GregorianCalendar(); System.out.println( cal.isLeapYear(1900) ); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |