java – 根据输入查找最小的整数

我有一项任务,可以找到用户输入的最小,最大和平均数.基本上,它们输入正整数,由空格分隔,Java滚动它们并将它们相加.我能够找到总和,平均值和最大整数,但是,我无法找到最小的整数.我认为解决这个问题的最好方法是将表示最小int的变量设置为等于表示循环外部最大int的变量.然后,在循环中,执行以下操作：

if(getInt < min)
        {
            min = getInt;
        }

其中getInt是用户输入的值,min是最小整数值.但是每次我运行它时,min都会返回0.

这是我的完整代码：

import java.util.Scanner;

public class exc5
{
    public static void main (String[] args)
    {  
        System.out.println("Write a list of nonnegative integers,each seperated by a space. To signal the end of the list,write a negative integer. The negative integer will not be counted");
        Scanner keyboard = new Scanner (System.in);
        keyboard.useDelimiter(" |n");

        int count = 0;
        int sum = 0;
        int max = 0;
        int min = max;
        double average = 0;

        boolean notNull = true;

        while(notNull == true)
        {
            int getInt = keyboard.nextInt();

            if(getInt < 0)
            {
                notNull = false;
            }  
            else
            {          
                if(getInt > max)
                {
                    max = getInt;
                }

                if(getInt < min)
                {
                    min = getInt;
                }

                sum += getInt;
                count++;
                average = (sum)/(count);
            }
        }

        System.out.println("Sum = " + sum);
        System.out.println("Average = " + average);
        System.out.println("Max = " + max);
        System.out.println("Minimum = " + min);
    }

}

任何帮助表示赞赏！

int max = 0;
        int min = max;

if(getInt < min)

int min = max;

int min = Integer.MAX_VALUE; // largest possible Java `int`