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所以我们都知道所有类都隐式地扩展了Object.接口怎么样？是否存在隐式超级接口？我说有.以下代码编译：
java.io.Serializable s1 = null;
java.io.Serializable s2 = null;
s1.equals(s2);
equals方法未在Serializable中声明,而是在Object中声明.由于接口只能扩展其他接口,而Object是一个类,而不是接口,因此必须有一些正在扩展的隐式接口.然后,Object类必须隐式实现这个隐式接口(哇,写起来很奇怪).
所以,问题是,这有多正确？
解决方法
Since interfaces can only extend other
interfaces,and Object is a class,not
an interface,there must be some
implicit interface that is being
extended.
引用Java Language Specification：
If an interface has no direct
superinterfaces,then the interface
implicitly declares a public abstract
member method m with signature s,
return type r,and throws clause t
corresponding to each public instance
method m with signature s,return type
r,and throws clause t declared in
Object,unless a method with the same
signature,same return type,and a
compatible throws clause is explicitly
declared by the interface. It is a compile-time error if the interface explicitly
declares such a method m in the case
where m is declared to be final in
Object.
这与你的“隐式超级接口”之间的区别在于Object有许多final和protected方法,你不能在接口中拥有这些修饰符.
（编辑：李大同）
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