java – 如何使用ExpectedException规则在一个测试中测试多个异
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对junit的ExpectedException规则的用法有疑问:
正如这里建议的那样:junit ExpectedException Rule @Rule
public ExpectedException exception = ExpectedException.none();
@Test
public void testFailuresOfClass() {
Foo foo = new Foo();
exception.expect(Exception.class);
foo.doStuff();
}
现在我需要在一个测试方法中测试几个异常,并在运行以下测试后得到一个绿色条,因此认为每个测试都通过了. @Test
public void testFailuresOfClass() {
Foo foo = new Foo();
exception.expect(IndexOutOfBoundsException.class);
foo.doStuff();
//this is not tested anymore and if the first passes everything looks fine
exception.expect(NullPointerException.class);
foo.doStuff(null);
exception.expect(MyOwnException.class);
foo.doStuff(null,"");
exception.expect(DomainException.class);
foo.doOtherStuff();
}
但是过了一会儿,我意识到第一次检查通过后,测试方法就会退出.至少可以说这是模棱两可的.在junit 3中,这很容易实现…… 如何使用ExpectedException规则在一个测试中测试多个异常? 解决方法
简短的回答:你做不到.
如果第一次调用–foo.doStuff() – 抛出异常,你永远不会到达foo.doStuff(null).你必须把你的测试分成几个(对于这个简单的情况,我建议回到简单的符号,没有ExpectedException): private Foo foo;
@Before
public void setUp() {
foo = new Foo();
}
@Test(expected = IndexOutOfBoundsException.class)
public void noArgsShouldFail() {
foo.doStuff();
}
@Test(expected = NullPointerException.class)
public void nullArgShouldFail() {
foo.doStuff(null);
}
@Test(expected = MyOwnException.class)
public void nullAndEmptyStringShouldFail() {
foo.doStuff(null,"");
}
@Test(expected = DomainException.class)
public void doOtherStuffShouldFail() {
foo.doOtherStuff();
}
如果你真的想要一个且只有一个测试,如果没有抛出错误你就会失败,并抓住你期望的东西: @Test
public void testFailuresOfClass() {
Foo foo = new Foo();
try {
foo.doStuff();
fail("doStuff() should not have succeeded");
} catch (IndexOutOfBoundsException expected) {
// This is what we want.
}
try {
foo.doStuff(null);
fail("doStuff(null) should not have succeeded");
} catch (NullPointerException expected) {
// This is what we want.
}
// etc for other failure modes
}
但是,这很快就会变得非常混乱,如果第一个期望失败,你就不会看到其他任何事情也会失败,这在排除故障时会很烦人. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
