java – 无法在Jersey中实现简单文件上传 – “使用POST注释资源

The following errors and warnings have been detected with resource and/or provider classes:
  SEVERE: Missing dependency for method public javax.ws.rs.core.Response com.foo.MyResource.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition) at parameter at index 0
  SEVERE: Missing dependency for method public javax.ws.rs.core.Response com.foo.MyResource.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition) at parameter at index 1
  SEVERE: Method,public javax.ws.rs.core.Response com.foo.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition),annotated with POST of resource,class com.foo.FS2Resource,is not recognized as valid resource method.
unavailable
com.sun.jersey.spi.inject.Errors$ErrorMessagesException
    at com.sun.jersey.spi.inject.Errors.processErrorMessages(Errors.java:170)

将输入参数映射到REST服务似乎存在问题？我已阅读文档并遵循了几个示例,我并没有偏离这些示例.

这是代码：

@Path("v1/")
public class FileUploadResource {


    @POST
    @Path("upload")
    @Consumes(MediaType.MULTIPART_FORM_DATA)
    @Produces({MediaType.APPLICATION_JSON})
    public Response uploadFile(
        @FormDataParam("file") InputStream is,@FormDataParam("file") FormDataContentDisposition detail) {

        String name = detail.getFileName();

        // do upload stuff
        String output = .... 

        return Response.status(200).entity(output).build();
    }

}

我为FormDataParams引入了“compile’c??om.sun.jersey.contribs：jersey-multipart：1.17.1’”.

编辑：我能够让它在泽西岛工作,但只有这种更原始的方式：

@POST
 @Path("upload")
 @Consumes(MediaType.MULTIPART_FORM_DATA)     
 @Produces(MediaType.TEXT_PLAIN)

 public Response uploadFile(final MimeMultipart file) {
   if (file == null) {
     return Response.status(Response.Status.BAD_REQUEST).entity("Must supply a valid file").build();

   try {
     for (int i = 0; i < file.getCount(); i++) {
       // ... do something with file.getBodyPart(i));
     }
     return Response.ok("done").build();
   } catch (final Exception e) {
     return Response.status(Response.Status.INTERNAL_SERVER_ERROR).entity(e).build();
   }
 }

这可能是一个充分的解决方法,但仍然希望找到问题的根源.