HtmlUnit模拟页面提交一个form
发布时间:2020-12-14 23:52:04 所属栏目:Java 来源:网络整理
导读:今天PHP站长网 52php.cn把收集自互联网的代码分享给大家,仅供参考。 public void submittingForm() throws Exception { final WebClient webClient = new WebClient(); // Get the first page final HtmlPage page1 = we
以下代码由PHP站长网 52php.cn收集自互联网 现在PHP站长网小编把它分享给大家,仅供参考 public void submittingForm() throws Exception { final WebClient webClient = new WebClient(); // Get the first page final HtmlPage page1 = webClient.getPage("http://some_url"); // Get the form that we are dealing with and within that form,// find the submit button and the field that we want to change. final HtmlForm form = page1.getFormByName("myform"); final HtmlSubmitInput button = form.getInputByName("submitbutton"); final HtmlTextInput textField = form.getInputByName("userid"); // Change the value of the text field textField.setValueAttribute("root"); // Now submit the form by clicking the button and get back the second page. final HtmlPage page2 = button.click(); } 以上内容由PHP站长网【52php.cn】收集整理供大家参考研究 如果以上内容对您有帮助,欢迎收藏、点赞、推荐、分享。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |