如何最好地在java中存储游戏配置变量

发布时间：2020-12-14 19:21:36 所属栏目：Java 来源：网络整理

导读：我正在编写一个小型java游戏,并将全局游戏设置存储在类结构中,如下所示： public class Globals { public static int tileSize = 16; public static String screenshotDir = "..somepath.."; public static String screenshotNameFormat = "gameNamexxx.

我正在编写一个小型java游戏,并将全局游戏设置存储在类结构中,如下所示：

public class Globals {
    public static int tileSize = 16;
    public static String screenshotDir = "..somepath..";
    public static String screenshotNameFormat = "gameNamexxx.png";
    public static int maxParticles = 300;
    public static float gravity = 980f;
    // etc
}

虽然这很方便,但我想知道这是否是可接受的模式.

最佳答案

将其存储在.properties文件中.

config.properties

tile.size=16
screenshot.dir=..somepath..

阅读它

// Make sure this happens only the first time you start your application
Properties properties = new Properties();
// You can use FileInputStream,ClassLoader.getResourceAsStream or a reader too
properties.load(...)

使用它

int tileSize = Integer.valueOf(properties.getProperty("tile.size"));
String screenshotDir = properties.getProperty("screenshot.dir");

为了简化操作并保持最小化,您还可以执行以下操作：

public class Globals {
    private static final Properties properties = new Properties();

    static {
        // do the loading here
    }

    public static final int TILE_SIZE = 
        Integer.valueOf(properties.getProperty("tile.size"));
    public static final String SCREENSHOT_DIR = 
        properties.getProperty("screenshot.dir");
    // etc
}

（编辑：李大同）

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