多个Regex @ Pattern的1个字段？

发布时间：2020-12-14 16:45:36 所属栏目：Java 来源：网络整理

导读：我试图将多个@Pattern注释应用于单个字段： @Pattern(regexp = "(?=.*[0-9])",message = "Password must contain one digit.")@Pattern(regexp = "(?=.*[a-z])",message = "Password must contain one lowercase letter.")@Pattern(regexp = "(?=.*[A-Z])",m

我试图将多个@Pattern注释应用于单个字段：

@Pattern(regexp = "(?=.*[0-9])",message = "Password must contain one digit.")
@Pattern(regexp = "(?=.*[a-z])",message = "Password must contain one lowercase letter.")
@Pattern(regexp = "(?=.*[A-Z])",message = "Password must contain one uppercase letter.")
@Pattern(regexp = "(?=S+$)",message = "Password must contain no whitespace.")
private String password;

但是,我不能这样做.我想要在密码字段上违反正则表达式约束的个别消息.这可能吗？

我的替代方法是使用JSF 2.0 f：validatorRegex标签.

解决方法

您可以使用@Pattern的内部@List注释：

@Pattern.List({
    @Pattern(regexp = "(?=.*[0-9])",message = "Password must contain one digit."),@Pattern(regexp = "(?=.*[a-z])",message = "Password must contain one lowercase letter."),@Pattern(regexp = "(?=.*[A-Z])",message = "Password must contain one uppercase letter."),@Pattern(regexp = "(?=S+$)",message = "Password must contain no whitespace.")
})
private String password;

（编辑：李大同）

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