java – 计算Joda时间的月差
发布时间:2020-12-14 16:23:31 所属栏目:Java 来源:网络整理
导读:在第4行代码(忽略空白和评论)和超出我计算两个日期之间的月份差异.这个工作,但看起来有点黑客.有没有更好的办法? int handleAllowance(LocalDate today) { int allowance = membership.allowance(); if (allowance == 0) return 0; // if update was last m
在第4行代码(忽略空白和评论)和超出我计算两个日期之间的月份差异.这个工作,但看起来有点黑客.有没有更好的办法?
int handleAllowance(LocalDate today) { int allowance = membership.allowance(); if (allowance == 0) return 0; // if update was last month (or earlier) int months = today.monthOfYear().getMaximumValue() - today.monthOfYear().getMinimumValue(); // yeah,12,but just to be 100% correct :-) int curMonth = (today.getYear() * months) + today. getMonthOfYear(); int updMonth = (lastAllowanceUpdate.getYear() * months) + lastAllowanceUpdate.getMonthOfYear(); if (curMonth > updMonth) { // ...and if today is on or past update day int updateDay = Math.min(allowanceDay,today.dayOfMonth().getMaximumValue()); if (today.getDayOfMonth() >= updateDay) { // number of months to give allowance (in the rare case this process fails to run for 2 months or more) int allowanceMonths = curMonth - updMonth; // give credits final int totalAllowance = allowance * allowanceMonths; giveCredits(totalAllowance); // update day lastAllowanceUpdate = lastAllowanceUpdate.plusMonths(allowanceMonths); // return the allowance given return totalAllowance; } } return 0; } 解决方法Months.monthsBetween( start.withDayOfMonth(1),end.withDayOfMonth(1)).getMonths() (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |