java – “包应包含内容类型部分[M1.13]”
发布时间：2020-12-14 16:21:32 所属栏目：Java 来源：网络整理
导读：我试图写入Excel文件,但我一直收到错误： Exception in thread “main” org.apache.poi.POIXMLException: org.apache.poi.openxml4j.exceptions.InvalidFormatException: Package should contain a content type part [M1.13] 根据我的理解,我错过了一个jar
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我试图写入Excel文件,但我一直收到错误：
根据我的理解,我错过了一个jar文件. 任何人都可以帮我识别它是哪个文件？ 附：我正在使用Netbeans. import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import javax.swing.JOptionPane;
import org.apache.poi.openxml4j.exceptions.InvalidFormatException;
import org.apache.poi.xssf.usermodel.XSSFCell;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
/**
*
* @author nicholaskissaun
*/
public class Tester {
public static void main (String args [])throws FileNotFoundException,IOException,InvalidFormatException{
int RowCount = 7,iChoice;
String sChoice;
XSSFSheet s;
XSSFRow row1;
XSSFWorkbook wb;
XSSFCell r1c1,r1c2,r1c8,r1Episodes;
FileInputStream fis = new FileInputStream("/Users/nicholaskissaun/Google Drive/Grade 11_12/Computer Science/Java/Term1/src/IA/Profiles/Becky/ShowDetails.xlsx");
wb = new XSSFWorkbook(fis);
s = wb.getSheetAt(0);
}
}
解决方法
使用文件扩展名来处理WorkSheet类型
String inputFilename = new File(path).getName();
switch (inputFilename.substring(inputFilename.lastIndexOf(".") + 1,inputFilename.length())) {
case "xls":
return readXLS(path);
case "xlsx":
return readXLSX(path);
default:
Log.e(TAG,"No XLS file chosen");
return "Please select valid "Excel" File"";
}
对于XLSX文件：使用XSSFWorkbook& XSSFSheet XSSFWorkbook workbook = new XSSFWorkbook(new FileInputStream(new File(path)));
XSSFSheet sheet = workbook.getSheetAt(0);
对于XLS文件：使用HSSFWorkbook& HSSFSheet HSSFWorkbook workbook = new HSSFWorkbook(new FileInputStream(new File(path)));
HSSFSheet sheet = workbook.getSheetAt(0);
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