java使用Hashtable过滤数组中重复值的方法

package org.eline.core.web.support;
import java.util.Hashtable;
/*****************************
 *
 * @author zdw
 *
 */
public class ObjectFilter
{
 public static void main(String[] args)
 {
  // String 测试
  String arr[] =
  { "13111","13112","13111" };
  ObjectFilter sf = new ObjectFilter();
  Object results[] = sf.filter(arr);
  System.out.println(results.length);
  for (int i = 0; i < results.length; ++i)
  {
   System.out.println(results[i]);
  }
  // 整形测试
  Integer arr2[] =
  { 1,3,5,7,1,2,4,5 };
  Object results2[] = sf.filter(arr2);
  for (int i = 0; i < results2.length; ++i)
  {
   System.out.println(results2[i]);
  }
 }
 /*************************
  * 过滤的方法
  *
  * @param arr
  *   要过滤的数组
  * @return
  */
 public Object[] filter(Object arr[])
 {
  Hashtable<Object,Object> hashtable = new Hashtable<Object,Object>();
  for (int i = 0; i < arr.length; ++i)
  {
   hashtable.put(arr[i],arr[i]);
  }
  Object results[] = null;
  results = hashtable.values().toArray();
  return results;
 }
}