Java Servlet生成JSON格式数据并用jQuery显示的方法
发布时间:2020-12-14 14:25:24 所属栏目:Java 来源:网络整理
导读:本篇章节讲解Java Servlet生成JSON格式数据并用jQuery显示的方法。供大家参考研究具体如下: 1、Servlet通过json-lib生成JSON格式的数据 import java.io.IOException;import java.io.PrintWriter;import java.util.*;import javax.servlet.Servlet
本篇章节讲解Java Servlet生成JSON格式数据并用jQuery显示的方法。分享给大家供大家参考,具体如下: 1、Servlet通过json-lib生成JSON格式的数据 import java.io.IOException; import java.io.PrintWriter; import java.util.*; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import json.Person; import net.sf.json.JSONArray; import net.sf.json.JSONObject; @WebServlet("/JSONServlet") public class JSONServlet extends HttpServlet { public JSONServlet() { super(); } public void destroy() { super.destroy(); // Just puts "destroy" string in log // Put your code here } public void doGet(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException { response.setContentType("application/x-json"); response.setCharacterEncoding("GBK"); PrintWriter out = response.getWriter(); ArrayList<Person> items=new ArrayList<Person>(); items.add(new Person(2,"jack")); items.add(new Person(2,"bob")); items.add(new Person(2,"alex")); JSONArray jsonArray=new JSONArray(); jsonArray.addAll(items); out.print(jsonArray.toString()); } public void doPost(HttpServletRequest request,IOException { doGet(request,response); } public void init() throws ServletException { // Put your code here } } 2、前端页面代码 <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script type="text/javascript" src="js/jquery-1.10.2.min.js"></script> <script type="text/javascript"> $(document).ready( function() { $("#kick").click( function() { $.ajax({ type : "post",//post方法 url : "JSONServlet",data : { "legs" : "2","name" : "aa" },//ajax成功的回调函数 success : function(returnData) { var arr = eval(returnData); $.each(arr,function(index,content) { $("#result").append( "<div>" + content.legs + "</div>" + "<div>" + content.name + "</div><hr/>"); }); } }); }); }); </script> </head> <body> <input type="button" id="kick" value="kick"> <div id="result"></div> </body> </html> jQuery也可以用.getJSON实现异步数据获取 <script type="text/javascript"> $(document).ready( function() { $("#kick").click(function() { $.getJSON("JSONServlet",function(returnData){ var arr = eval(returnData); $("#result").html("");//清空info内容 $.each(arr,content) { $("#result").append( "<div>" + content.legs + "</div>" + "<div>" + content.name + "</div><hr/>"); }); }); }); }); </script> 希望本文所述对大家JSP程序设计有所帮助。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |