java – 用jackson删除JSON元素
发布时间：2020-12-14 05:50:30 所属栏目：Java 来源：网络整理
导读：我有一个特定的 JSON节点,对应于import org.codehaus.jackson.JsonNode,而不是 import org.codehaus.jackson.map.JsonNode. [ { "givenName": "Jim","formattedName": "jimJackson","familyName": null,"middleName": "none","honorificPrefix": "mr","honor
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我有一个特定的
JSON节点,对应于import org.codehaus.jackson.JsonNode,而不是
import org.codehaus.jackson.map.JsonNode. [
{
"givenName": "Jim","formattedName": "jimJackson","familyName": null,"middleName": "none","honorificPrefix": "mr","honorificSuffix": "none"
},{
"givenName": "john","formattedName": "johnLasher",{
"givenName": "carlos","formattedName": "carlosAddner","honorifiPrefix": "mr",{
"givenName": "lisa","formattedName": "lisaRay","honorificPrefix": "mrs",{
"givenName": "bradshaw","formattedName": "bradshawLion",{
"givenName": "phill","formattedName": "phillKane",{
"givenName": "Gabriel","formattedName": "gabrielMoosa","honorificSuffix": "none"
}
]
我想从上述数组的所有JSON节点中删除“familyName”和“middleName”.有没有办法实现这一点？ 解决方法
我没有测试过这个,但我觉得这样做会做你想要的：
import org.codehaus.jackson.node.ObjectNode;
// ...
for (JsonNode personNode : rootNode) {
if (personNode instanceof ObjectNode) {
ObjectNode object = (ObjectNode) personNode;
object.remove("familyName");
object.remove("middleName");
}
}
您也可以使用Jackon的原始解析API更有效地执行此操作,但代码将会更加复杂. （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |