java – RMI NotSerializableException虽然它是一个远程对象
发布时间:2020-12-14 05:40:11 所属栏目:Java 来源:网络整理
导读:我正在编写一个基于RMI的小型聊天应用程序. 这个想法是:客户端在服务器上注册自己,并且每当服务器从客户端收到消息时,他将该消息推送给所有其他客户端. 但是我收到一个NotSerializableException虽然,对象,我作为一个方法参数传递实现Remote接口. 这是一些代
我正在编写一个基于RMI的小型聊天应用程序.
这个想法是:客户端在服务器上注册自己,并且每当服务器从客户端收到消息时,他将该消息推送给所有其他客户端. 但是我收到一个NotSerializableException虽然,对象,我作为一个方法参数传递实现Remote接口. 这是一些代码: (ClientChat)界面: public interface ChatClient extends Remote { } (ClientChat)执行: public class ChatClientImpl implements ChatClient { ChatServer chatServ; String clientName; public ChatClientImpl(String clientName,ChatServer chatServ) { this.chatServ = chatServ; this.clientName = clientName; try { this.chatServ.registriereClient(this); } catch (RemoteException e) { e.printStackTrace(); } } } (ServerChat)接口 public interface ChatServer extends Remote { void registriereClient(ChatClient client) throws RemoteException; } (ServerChat)实现 public class LobbyChatServerImpl implements ChatServer { ArrayList<ChatClient> clientListe = null; @Override public void registriereClient(ChatClient client) { System.out.println("Client registriert"); this.clientListe.add(client); } } 客户: public static void main(String[] args) { ChatServer lobbyChatServer = null; try { Registry registry = LocateRegistry.getRegistry(Server.RMI_PORT); lobbyChatServer = (ChatServer) registry.lookup("LobbyChatServer"); } catch (RemoteException e) { e.printStackTrace(); } catch (NotBoundException e) { e.printStackTrace(); } ChatClient lobbyChat = new ChatClientImpl(name,lobbyChatServer); } 服务器: public static void main(String[] args) { try { if (System.getSecurityManager() == null) { System.setSecurityManager(new RMISecurityManager()); } Registry registry = LocateRegistry.getRegistry(RMI_PORT); ChatServer lobbyChatStub = (ChatServer)UnicastRemoteObject.exportObject(new LobbyChatServerImpl(),0); registry.bind("LobbyChatServer",lobbyChatStub); } catch (RemoteException e) { e.printStackTrace(); } catch (AlreadyBoundException e) { e.printStackTrace(); } } 例外: java.rmi.MarshalException: error marshalling arguments; nested exception is: java.io.NotSerializableException: de.XX.Chat.ChatClientImpl at sun.rmi.server.UnicastRef.invoke(UnicastRef.java:156) at java.rmi.server.RemoteObjectInvocationHandler.invokeRemoteMethod(RemoteObjectInvocationHandler.java:194) at java.rmi.server.RemoteObjectInvocationHandler.invoke(RemoteObjectInvocationHandler.java:148) at $Proxy0.registriereClient(Unknown Source) at de.XX.Chat.ChatClientImpl.<init>(ChatClientImpl.java:19) at de.XX.Client.main(Client.java:49) Caused by: java.io.NotSerializableException: de.XX.Chat.ChatClientImpl at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1180) at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:346) at sun.rmi.server.UnicastRef.marshalValue(UnicastRef.java:292) at sun.rmi.server.UnicastRef.invoke(UnicastRef.java:151) ... 5 more 如前所述,我不知道为什么我会得到这样的异常,虽然ChatClientImpl已经是远程. 希望你可以帮我:) 解决方法
作为远程方法的参数或结果传递的对象必须是:
>可串行化(或Externalizable),或 你们都不是然而,由于它实现了一个远程接口,你明确地意图(2).扩展UnicastRemoteObject的对象在构建时自动导出.不必通过UnicastRemoteObject.exportObject()显式导出的对象. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |