java – RMI NotSerializableException虽然它是一个远程对象
发布时间:2020-12-14 05:40:11 所属栏目:Java 来源:网络整理
导读:我正在编写一个基于RMI的小型聊天应用程序. 这个想法是:客户端在服务器上注册自己,并且每当服务器从客户端收到消息时,他将该消息推送给所有其他客户端. 但是我收到一个NotSerializableException虽然,对象,我作为一个方法参数传递实现Remote接口. 这是一些代
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我正在编写一个基于RMI的小型聊天应用程序.
这个想法是:客户端在服务器上注册自己,并且每当服务器从客户端收到消息时,他将该消息推送给所有其他客户端. 但是我收到一个NotSerializableException虽然,对象,我作为一个方法参数传递实现Remote接口. 这是一些代码: (ClientChat)界面: public interface ChatClient extends Remote
{
}
(ClientChat)执行: public class ChatClientImpl implements ChatClient
{
ChatServer chatServ;
String clientName;
public ChatClientImpl(String clientName,ChatServer chatServ) {
this.chatServ = chatServ;
this.clientName = clientName;
try {
this.chatServ.registriereClient(this);
} catch (RemoteException e) {
e.printStackTrace();
}
}
}
(ServerChat)接口 public interface ChatServer extends Remote
{
void registriereClient(ChatClient client) throws RemoteException;
}
(ServerChat)实现 public class LobbyChatServerImpl implements ChatServer
{
ArrayList<ChatClient> clientListe = null;
@Override
public void registriereClient(ChatClient client) {
System.out.println("Client registriert");
this.clientListe.add(client);
}
}
客户: public static void main(String[] args) {
ChatServer lobbyChatServer = null;
try {
Registry registry = LocateRegistry.getRegistry(Server.RMI_PORT);
lobbyChatServer = (ChatServer) registry.lookup("LobbyChatServer");
} catch (RemoteException e) {
e.printStackTrace();
} catch (NotBoundException e) {
e.printStackTrace();
}
ChatClient lobbyChat = new ChatClientImpl(name,lobbyChatServer);
}
服务器: public static void main(String[] args) {
try {
if (System.getSecurityManager() == null) {
System.setSecurityManager(new RMISecurityManager());
}
Registry registry = LocateRegistry.getRegistry(RMI_PORT);
ChatServer lobbyChatStub = (ChatServer)UnicastRemoteObject.exportObject(new LobbyChatServerImpl(),0);
registry.bind("LobbyChatServer",lobbyChatStub);
} catch (RemoteException e) {
e.printStackTrace();
} catch (AlreadyBoundException e) {
e.printStackTrace();
}
}
例外: java.rmi.MarshalException: error marshalling arguments; nested exception is:
java.io.NotSerializableException: de.XX.Chat.ChatClientImpl
at sun.rmi.server.UnicastRef.invoke(UnicastRef.java:156)
at java.rmi.server.RemoteObjectInvocationHandler.invokeRemoteMethod(RemoteObjectInvocationHandler.java:194)
at java.rmi.server.RemoteObjectInvocationHandler.invoke(RemoteObjectInvocationHandler.java:148)
at $Proxy0.registriereClient(Unknown Source)
at de.XX.Chat.ChatClientImpl.<init>(ChatClientImpl.java:19)
at de.XX.Client.main(Client.java:49)
Caused by: java.io.NotSerializableException: de.XX.Chat.ChatClientImpl
at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1180)
at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:346)
at sun.rmi.server.UnicastRef.marshalValue(UnicastRef.java:292)
at sun.rmi.server.UnicastRef.invoke(UnicastRef.java:151)
... 5 more
如前所述,我不知道为什么我会得到这样的异常,虽然ChatClientImpl已经是远程. 希望你可以帮我:) 解决方法
作为远程方法的参数或结果传递的对象必须是:
>可串行化(或Externalizable),或 你们都不是然而,由于它实现了一个远程接口,你明确地意图(2).扩展UnicastRemoteObject的对象在构建时自动导出.不必通过UnicastRemoteObject.exportObject()显式导出的对象. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
