java – 如果构造函数的参数是非法的,则阻止类的实例化？

Is there any other way of doing it ? Maybe from inside the constructor itself ?

是.我建议从构造函数中抛出异常

public class Person
{


    int age;
    public Person(int age) throws Exception
    {
       if(age <= 0)
       {

          throw new Exception("Age is not allowed");
       }
       // Do some stuffs
       this.age = age;
    }

}

编辑：

您也可以按照Till Helge Helwig的建议使用IllegalArgumentException

public class Person
{


    int age;
    public Person(int age) throws IllegalArgumentException
    {
       if(age <= 0)
       {

          throw new IllegalArgumentException("Age is not allowed");
       }
       // Do some stuffs
       this.age = age;
    }

}