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如何在JAVA中对JSONArray进行排序

发布时间:2020-12-14 05:04:11 所属栏目:Java 来源:网络整理
导读:参见英文答案 Android how to sort JSONArray of JSONObjects6 如何按对象的字段排序对象的JSONArray? 输入: [ { "ID": "135","Name": "Fargo Chan" },{ "ID": "432","Name": "Aaron Luke" },{ "ID": "252","Name": "Dilip Singh" }]; 所需输出(按“名称”
参见英文答案 > Android how to sort JSONArray of JSONObjects6
如何按对象的字段排序对象的JSONArray?

输入:

[
    { "ID": "135","Name": "Fargo Chan" },{ "ID": "432","Name": "Aaron Luke" },{ "ID": "252","Name": "Dilip Singh" }
];

所需输出(按“名称”字段排序):

[
    { "ID": "432","Name": "Dilip Singh" }
    { "ID": "135",];

解决方法

尝试这个:
//I assume that we need to create a JSONArray object from the following string
    String jsonArrStr = "[ { "ID": "135","Name": "Fargo Chan" },{ "ID": "432","Name": "Aaron Luke" },{ "ID": "252","Name": "Dilip Singh" }]";

    JSONArray jsonArr = new JSONArray(jsonArrStr);
    JSONArray sortedJsonArray = new JSONArray();

    List<JSONObject> jsonValues = new ArrayList<JSONObject>();
    for (int i = 0; i < jsonArr.length(); i++) {
        jsonValues.add(jsonArr.getJSONObject(i));
    }
    Collections.sort( jsonValues,new Comparator<JSONObject>() {
        //You can change "Name" with "ID" if you want to sort by ID
        private static final String KEY_NAME = "Name";

        @Override
        public int compare(JSONObject a,JSONObject b) {
            String valA = new String();
            String valB = new String();

            try {
                valA = (String) a.get(KEY_NAME);
                valB = (String) b.get(KEY_NAME);
            } 
            catch (JSONException e) {
                //do something
            }

            return valA.compareTo(valB);
            //if you want to change the sort order,simply use the following:
            //return -valA.compareTo(valB);
        }
    });

    for (int i = 0; i < jsonArr.length(); i++) {
        sortedJsonArray.put(jsonValues.get(i));
    }

排序的JSONArray现在存储在sortedJsonArray对象中.

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