php – 强制服务返回json而不是默认的html
发布时间:2020-12-13 16:00:11 所属栏目:PHP教程 来源:网络整理
导读:我希望能够在php中编写相当于此curl命令的代码: curl -F out=json --form-string 'content=!DOCTYPE htmlhtmlheadtitlecheck it/title/headbody/body/html' http://validator.w3.org/nu/ 这个curl命令按预期返回json. 也许我在这里遗漏了他们的文档: https
我希望能够在php中编写相当于此curl命令的代码:
curl -F out=json --form-string 'content=<!DOCTYPE html><html><head><title>check it</title></head><body></body></html>' http://validator.w3.org/nu/ 这个curl命令按预期返回json. 我现在的问题是Web服务返回html而不是json. $html = "<!DOCTYPE html><html><head><title>test</title></head><body></body></html>"; $endPoint = "http://validator.w3.org/nu/"; $timeout = 5000; $ch = curl_init(); curl_setopt($ch,CURLOPT_URL,$endPoint); curl_setopt($ch,CURLOPT_TIMEOUT_MS,$timeout); curl_setopt($ch,CURLOPT_POST,true); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt($ch,CURLOPT_BINARYTRANSFER,true); //curl_setopt($ch,CURLOPT_HTTPHEADER,array('Accept: application/json','Content-Type: application/json')); curl_setopt($ch,array('Accept: application/json')); curl_setopt($ch,CURLOPT_POSTFIELDS,array('content' => $html,'out' => 'json')); $output = curl_exec($ch); if(curl_errno($ch)) { echo curl_error($ch); } curl_close($ch); error_log(__FILE__. ": " . __LINE__ . ": " . var_export($output,true)); echo $output; 阅读Ignacio问题后,我将从w3c文档页面更新此信息: 在他们的文档中他们说html字符串应该在http体中发送,在他们的java库中他们使用这个: String response = null; String source = "your html here"; HttpResponse<String> uniResponse = Unirest.post("http://localhost:8080/vnu") .header("User-Agent","Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML,like Gecko) Chrome/41.0.2272.101 Safari/537.36") .header("Content-Type","text/html; charset=UTF-8") .queryString("out","gnu") .body(source) .asString(); response = uniResponse.getBody(); 这可能是你的暗示吗?只是为了让你知道我试过了两个 http://validator.w3.org/nu/?out=json 和 http://validator.w3.org/nu/ 端点(作为上面php脚本中$endPoint变量的值). 解决方法
要获得您要查找的结果,您必须将数据作为multipart / form-data发送(您可以查看
validator page或curl发送的请求,以查看数据是作为multipart / form-data发送的)为此,以此为例:
$url = 'http://validator.w3.org/nu/'; $html = '<!DOCTYPE html><html><head><title>test</title></head><body></body></html>'; $boundary = 'your-boundary'; $body = '--' . $boundary . "rn"; // set the "out" as "json" $body .= 'Content-Disposition: form-data; name="out"' . "rn" . "rn"; $body .= 'json' . "rn"; $body .= "--" . $boundary ."rn"; // set the "content" $body .= 'Content-Disposition: form-data; name="content"' . "rn" . "rn"; $body .= $html . "rn"; $body .= "--" . $boundary . "--" . "rn" . "rn"; $ch = curl_init(); curl_setopt($ch,$url); curl_setopt($ch,array('Content-Type: multipart/form-data; boundary='.$boundary)); curl_setopt($ch,$body); echo curl_exec($ch); curl_close($ch); 然后你会得到这样的东西: { "messages": [{ "type": "info","message": "The Content-Type was “text/html”. Using the HTML parser." },{ "type": "info","message": "Using the schema for HTML with SVG 1.1,MathML 3.0,RDFa 1.1,and ITS 2.0 support." }],"source": { "type": "text/html","encoding": "utf-8","code": "<!DOCTYPE html><html><head><title>test</title></head><body></body></html>" } } 希望能有所帮助. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |