php多维数组按类型和日期出现的次数

发布时间：2020-12-13 15:57:26 所属栏目：PHP教程来源：网络整理

导读：我有以下数组： Array([0] = Array ( [0] = 2015-07-18 [1] = 22 SSH )[1] = Array ( [0] = 2015-07-18 [1] = 80 HTTP )[2] = Array ( [0] = 2015-07-18 [1] = 3389 Remote Desktop )[3] = Array ( [0] = 2015-07-19 [1] = 3389 Remote Desktop )[4] = Array

我有以下数组：

Array
(
[0] => Array
    (
        [0] => 2015-07-18
        [1] => 22 SSH
    )

[1] => Array
    (
        [0] => 2015-07-18
        [1] => 80 HTTP
    )

[2] => Array
    (
        [0] => 2015-07-18
        [1] => 3389 Remote Desktop
    )

[3] => Array
    (
        [0] => 2015-07-19
        [1] => 3389 Remote Desktop
    )

[4] => Array
    (
        [0] => 2015-07-19
        [1] => 3389 Remote Desktop
    )
)

并且需要按日期和出现次数计算的数据采用以下格式：

array(4) {
  [0]=>
  array(1) {
    [0]=> "3389 Remote Desktop"
    [1]=> "1,2"
  }
  [1]=>
  array(1) {
    [0]=> "22 SSH"
    [1]=> "1,0"
  }
  [2]=>
  array(1) {
    [0]=> "80 HTTP"
    [1]=> "1,0"
  }
}

我怎样才能做到这一点？我可以计算所有出现但未按日期和类型分组,如下所示：

$counts = array();
foreach( $stack_stats_timeline as $value) {
    foreach( $value as $k => $v) {
        if( !isset( $counts[$k])) $counts[$k] = array();
        if( !isset( $counts[$k][$v])) $counts[$k][$v] = 0;
        $counts[$k][$v] += 1;
    }
}

解决方法

我想这会帮助你让它发挥作用

$result = array();
$count = 1;
foreach ($arr as $key => &$value) {
    $hash = $value[1];
    $result[$hash][0] = $value[1];
    $result[$hash][1][$value[0]] = (isset($result[$hash][1][$value[0]])) ? $count + 1 : $count;
}
print_r(array_values($result));

（编辑：李大同）

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