php – Codeigniter:如何获取文件的文件名
发布时间:2020-12-13 13:05:49 所属栏目:PHP教程 来源:网络整理
导读:我是Codeigniter新手,我试图获取上传图像的文件名,以便我可以将其保存在数据库中. 我有两个模型,homemodel处理我的数据库,image_upload_model处理图像上传. 一切正常,但我不知道如何将图像文件名发布到数据库 image_upload_model.php ?phpclass Image_upload
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我是Codeigniter新手,我试图获取上传图像的文件名,以便我可以将其保存在数据库中.
我有两个模型,homemodel处理我的数据库,image_upload_model处理图像上传. 一切正常,但我不知道如何将图像文件名发布到数据库 image_upload_model.php <?php
class Image_upload_model extends CI_Model {
var $image_path;
//constructor containing the image path
function Image_upload_model() {
$this->image_path = realpath(APPPATH.'../assets/img');
}
//uploading the file
function do_upload() {
$config = array(
'allowed_types' => 'jpg|jpeg|gif|png','upload_path' => $this->image_path
);
$this->load->library('upload',$config);
$this->upload->do_upload();
}
}
?>
homemodel.php <?php
class homeModel extends CI_Model {
//inserting into the table tenants
function addTenants() {
$this->load->model('Image_upload_model');
$data = array(
'Fname' => $this->input->post('Fname'),'Lname' => $this->input->post('Lname'),'contact' => $this->input->post('contact'),'email' => $this->input->post('email'),'location' => $this->input->post('location'),'img_url' => " "//the filename of the image should go here
);
$this->db->insert('tenants',$data);
}
}
?>
控制器 <?php
class HomeController extends CI_Controller {
public function index() {
$this->load->helper('form');
$this->load->helper('html');
$this->load->model('homemodel');
$this->load->model('Image_upload_model');
if ($this->input->post('submit') == 'Submit') {
$this->homemodel->addTenants();
echo 'inserted';
$this->Image_upload_model->do_upload();
echo 'image uploaded';
}
$this->load->view('index.php');
}
}
?>
任何帮助表示赞赏,谢谢!
你可以得到这样的文件名
$upload_data = $this->upload->data(); $file_name = $upload_data['file_name']; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
