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<div class="codetitle"><a style="CURSOR: pointer" data="55880" class="copybut" id="copybut55880" onclick="doCopy('code55880')"> 代码如下:<div class="codebody" id="code55880">
<?php
$password = "1234"; // 这里是密码
$p = "";
if(isset($_COOKIE["isview"]) and $_COOKIE["isview"] == $password){
$isview = true;
}else{
if(isset($_POST["pwd"])){
if($_POST["pwd"] == $password){
setcookie("isview",$_POST["pwd"],time()+3600*3);
$isview = true;
}else{
$p = (empty($_POST["pwd"])) ? "需要密码才能查看，请输入密码。" : "密码不正确，请重新输入。";
}
}else{
$isview = false;
$p = "请输入密码查看，获取密码可联系我。";
}
}
if($isview){ ?>
这里是密码成功后显示的地方
<?php }else{ ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns=" http://www.w3.org/1999/xhtml">
编程之家提醒你输入密码
<style type="text/css">
<div class="passport">
<div style="padding-top:20px;">
<form action="?yes" method="post" style="margin:0px;">输入查看密码
<?php echo $p; ?>
<?php
} ?>
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