PHP响应post请求上传文件的方法

PHP教程
function send_file($url,$post = '',$file = '') {
  $eol = "rn";
  $mime_boundary = md5 ( time () );
  $data = '';
  $confirmation = '';
  date_default_timezone_set ( "Asia/Shanghai" );
  $time = date ( "Y-m-d H:i:s " );
  $post ["filename"] = $file [filename];
  foreach ( $post as $key => $value ) {
    $data .= '--' . $mime_boundary . $eol;
    $data .= 'Content-Disposition: form-data; ';
    $data .= "name=" . $key . $eol . $eol;
    $data .= $value . $eol;
  }
  $data .= '--' . $mime_boundary . $eol;
  $data .= 'Content-Disposition: form-data; name=' . $file [name] . '; filename=' . $file [filename] . $eol;
  $data .= 'Content-Type: text/plain' . $eol;
  $data .= 'Content-Transfer-Encoding: binary' . $eol . $eol;
  $data .= $file [filedata] . $eol;
  $data .= "--" . $mime_boundary . "--" . $eol . $eol;
  $params = array ('http' => array ('method' => 'POST','header' => 'Content-Type: multipart/form-data;boundary=' . $mime_boundary . $eol,'content' => $data ) );
  $ctx = stream_context_create ( $params );
  $response = file_get_contents ( $url,FILE_TEXT,$ctx );
  return $response;
}