PHP编程：PHP中实现获取IP和地理位置类分享
发布时间：2020-12-13 02:24:28 所属栏目：PHP教程 来源：网络整理
导读：《PHP中实现获取IP和地理位置类分享》要点： 本文介绍了PHP中实现获取IP和地理位置类分享，希望对您有用。如果有疑问，可以联系我们。 发现之前有一个脚本没有写完,简单扩充了一下. 获取IP使用的是经典的逻辑,地舆定位使用的是SINA的通用接口. PHP学习 使用
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《PHP中实现获取IP和地理位置类分享》要点： 发现之前有一个脚本没有写完,简单扩充了一下. 使用办法详见源码：
代码如下:
<必修php /* ?* GET LOCATION BY SINA IP INTERFACE ?* ?*????????????? @SOULTEARY 2013.04.14 ?*/ classIP { ??? private $args=array(); ? ??? function__construct() ??? { ??????? $this->args=self::init_args(func_get_args()); ??????? $ip=self::GetIP(); ? ??????? $ret=preg_match_all('/(d+.){3}d+/i',$ip,$result); ??????? if(!$ret){ ??????????? returnfalse; ??????? }else{ ??????????? $result=$result[0]; ??????? } ? ??????? if(isset($this->args['ONLYIP'])&&$this->args['ONLYIP']==true){ ? ??????????? if(isset($this->args['FORMAT'])&&$this->args['FORMAT']=='JSON'){ ??????????????? $result=json_encode($result); ??????????? }else{ ??????????????? $result=implode(',',$result); ??????????? } ??????????? if(isset($this->args['ECHO'])&&$this->args['ECHO']==true){ ??????????????? echo$result; ??????????????? returntrue; ??????????? }else{ ??????????????? return$result; ??????????? } ??????? }else{ ? ??????????? $apiURL='http://int.dpool.sina.com.cn/iplookup/iplookup.php必修ip='.$result[0]; ??????????? if(isset($this->args['FORMAT'])&&$this->args['FORMAT']=='JSON'){ ??????????????? $apiURL.='&format=json'; ??????????????? $return=$this->ipCURL($apiURL); ??????????? }else{ ??????????????? $return=$this->ipCURL($apiURL); ??????????????? $return=iconv("GBK//IGNORE","UTF-8",$return); ??????????? } ? ??????????? if(isset($this->args['ECHO'])&&$this->args['ECHO']==true){ ??????????????? echo$return; ??????????????? returntrue; ??????????? }else{ ??????????????? return$return; ??????????? } ? ??????? } ? ??? } ? ??? public functioninit_args($args) ??? { ??????? $result=array(); ??????? for($i=0,$n=count($args);$i<$n;$i++){ ??????????? $result=self::associative_push($args[$i],$result); ??????? } ??????? return$result; ??? } ? ??? public functionassociative_push($arr,$tmp) ??? { ??????? if(is_array($tmp)){ ??????????? foreach($tmpas$key=>$value){ ??????????????? $arr[$key]=$value; ??????????? } ??????????? return$arr; ??????? } ??????? returnfalse; ??? } ? ??? public functionGetIP() ??? { ??????? if(isset($_SERVER['HTTP_X_FORWARDED_FOR'])&&$_SERVER['HTTP_X_FORWARDED_FOR']&&strcasecmp($_SERVER['HTTP_X_FORWARDED_FOR'],'unknown')){ ??????????? return$_SERVER['HTTP_X_FORWARDED_FOR']; ??????? }elseif(isset($_SERVER['REMOTE_ADDR'])&&$_SERVER['REMOTE_ADDR']&&strcasecmp($_SERVER['REMOTE_ADDR'],'unknown')){ ??????????? return$_SERVER['REMOTE_ADDR']; ??????? } ??? } ? ??? private functionipCURL($url) ??? { ??????? $ch=curl_init(); ??????? curl_setopt($ch,CURLOPT_URL,$url); ??????? curl_setopt($ch,CURLOPT_HEADER,0); ??????? ob_start(); ??????? curl_exec($ch); ??????? curl_close($ch); ??????? $result=ob_get_contents(); ??????? ob_end_clean(); ??????? return$result; ??? } } ? 必修> <!DOCTYPE html> <html> <head> ??? <meta charset="utf8"> ??? <title>demo</title> ??? <script type="text/javascript"> ??????? varip="<必修php new IP(array('ONLYIP'=>true,'ECHO'=>true));必修>"; ??????? vardata=<必修php newIP(array('FORMAT'=>'JSON','ECHO'=>true));必修>; ??????? varresult=''; ??????? for(oo indata){ ??????????? result+=oo+':'+data[oo]+"n"; ??????? } ??????? alert(result+ip); ??? </script> </head> <body> <h1>CODE:</h1> ? <h2>GETIP</h2> ? <p>'ONLYIP'=>true,'ECHO'=>true</p> ? <p><必修phpnewIP(array('ONLYIP'=>true,'ECHO'=>true));必修></p> ? <P>'ONLYIP'=>true,'FORMAT'=>'JSON','ECHO'=>true</P> ? <p><必修phpnewIP(array('ONLYIP'=>true,'ECHO'=>true));必修></p> ? <h2>GET Location</h2> ? <p>'ECHO'=>true</p> ? <p><必修phpnewIP(array('ECHO'=>true));必修></p> ? <p>'FORMAT'=>'JSON','ECHO'=>true</p> ? <p><必修php newIP(array('FORMAT'=>'JSON','ECHO'=>true));必修></p> </body> </html> 欢迎参与《PHP中实现获取IP和地理位置类分享》讨论，分享您的想法，编程之家 52php.cn为您提供专业教程。 （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |