ThinkPHP中使用ajax接收json数据的方法

function ajax(id,pic){
??? //由于ThinkPHP不解析JavaScript里的ThinkPHP常量,所以需要先在这里定义.
var URL='__URL__';
??????? $.ajax({
??????????? url: URL+'/returnAjax/id/'+id,//提交拜访的URL
??????????? type: 'GET',//提交的方法
??????????? dataType: 'text',//返回的内容的类型,由于PHP文件是直接echo的,那么这里就是text
??????????? timeout: 1000,//超时时间
??????????? error: function(){ //如果出错,执行函数
??????????????? alert('Error loading XML document');
??????????? },
??????????? success: function(data){
??????????????? //alert(data);//如果成功,弹出数据
??????????????? writeHtml(data,pic);
??????????? }
??????? });
}
function writeHtml(data,pic){
??? var product = eval('(' + data + ')'); //即使不引入json.js也可以转成json对象?
??? //alert($("#cate_pic").attr("src"));
??? $("#cate_pic").attr("src","../images/"+pic);
??? $("#product_pic").attr("src","../Attachments/product/"+product.attachpath+"/"+product.attachthumb);
??? $("#product_subject").html(product.subject);
??? $("#product_content").html(product.content);
}

public function returnAjax(){?
??????? $id = $_GET['id'];?
??????? $Product=D('Product')->where('id='.$id)->find();?
??????? //返回一个json格式的数据集?
??????? echo json_encode($Product);?
//print_r(json_encode($Product));?
}

??
{
??? "id":"9",
??? "userid":"1",
??? "cid":"10",
??? "subject":"1111",
??? "color":"",
??? "spec":"",
??? "size":"",
??? "keywords":"",
??? "content":"<p>1111</p>",
??? "meno":"1111",
??? "attachpath":"200903",
??? "attachment":"49d1d86e68d31.png",
??? "attachthumb":"49d1d86e68d31_thumb.png"
}