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PHP字符串word末字符实现大小写互换的方法

发布时间:2020-12-13 02:08:50 所属栏目:PHP教程 来源:网络整理
导读:《PHP实战:PHP字符串word末字符实现大小写互换的方法》要点: 本文介绍了PHP实战:PHP字符串word末字符实现大小写互换的方法,希望对您有用。如果有疑问,可以联系我们。 PHP编程 本篇章节讲解PHP字符串word末字符实现大小写互换的办法.分享给大家供大家

《PHP实战:PHP字符串word末字符实现大小写互换的方法》要点:
本文介绍了PHP实战:PHP字符串word末字符实现大小写互换的方法,希望对您有用。如果有疑问,可以联系我们。

PHP编程本篇章节讲解PHP字符串word末字符实现大小写互换的办法.分享给大家供大家参考.具体实现办法如下:

PHP编程一、要求:
给出一个字符串如 “A journey of,a thousand 'miles' must can't "begin" with a single step.”,通过 PHP 程序处理变成 “a journeY oF,A thousanD 'mileS' musT can'T "begiN" witH A singlE steP.”

PHP编程这里需要注意:

PHP编程1、每个单词最后的字符如果是大写就变成小写,如果是小写就变成大写.
2、需要考虑类似? can't 这种形式的转换.
3、标点符号(只考虑,' " . ;)不用变化.

PHP编程二、参考算法如下:

代码如下:
<?php
??? function convertLastChar($str) {
??????? $markArr = array(",","' ","" ",". ","; ");
??????? $ret = "";
??????? for ($i = 0,$j = strlen($str); $i < $j; $i++) {
??????????? if ($i < $j - 2) {
??????????????? $afterStr = $str{$i + 1} . $str{$i + 2};
??????????? } else if ($i < $j - 1) {
??????????????? $afterStr = $str{$i + 1} . " ";
??????????? }
??????????? if (in_array($afterStr,$markArr)
??????????????? || $i == $j - 1
??????????????? || $str{$i + 1} == " ") {
??????????????? $ret .= strtoupper($str{$i}) === $str{$i}
??????????????????? ? strtolower($str{$i})
??????????????????? : strtoupper($str{$i});
??????????? } else {
??????????????? $ret .= $str{$i};
??????????? }
??????? }
??????? return $ret;
??? }
?>

PHP编程测试代码如下:

代码如下:
<?php

PHP编程??? //test
??? $str1 = "A journey of,a thousand 'miles' must can't "begin" with a single step.";
??? $str2 = "A journey of,a thousand 'miles' must can't "begin" with a single step. ";
??? $str3 = "A journey of,a thousand 'miles' must can't "begin" with a single step. a ";
??? $str4 = "A journey of,a thousand 'miles' must can't "begin" with a single step. a B";
??? $str5 = "A journey of,a thousand 'miles' must can't "begin" with a single step. a b'";
??? $str6 = "A journey of,a thousand 'miles' must can't "begin" with a single step. a B"";

PHP编程??? echo "source:<br/>" . $str1 . "<br/>result:<br/>" . convertLastChar($str1) . "<br/><br/>";
??? echo "source:<br/>" . $str2 . "<br/>result:<br/>" . convertLastChar($str2) . "<br/><br/>";
??? echo "source:<br/>" . $str3 . "<br/>result:<br/>" . convertLastChar($str3) . "<br/><br/>";
??? echo "source:<br/>" . $str4 . "<br/>result:<br/>" . convertLastChar($str4) . "<br/><br/>";
??? echo "source:<br/>" . $str5 . "<br/>result:<br/>" . convertLastChar($str5) . "<br/><br/>";
??? echo "source:<br/>" . $str6 . "<br/>result:<br/>" . convertLastChar($str6) . "<br/><br/>";
?>

PHP编程运行结果如下:

代码如下:
source:
A journey of,a thousand 'miles' must can't "begin" with a single step.
result:
a journeY oF,A thousanD 'mileS' musT can'T "begiN" witH A singlE steP.

PHP编程source:
A journey of,a thousand 'miles' must can't "begin" with a single step.
result:
a journeY oF,A thousanD 'mileS' musT can'T "begiN" witH A singlE steP.

PHP编程source:
A journey of,a thousand 'miles' must can't "begin" with a single step. a
result:
a journeY oF,A thousanD 'mileS' musT can'T "begiN" witH A singlE steP. A

PHP编程source:
A journey of,a thousand 'miles' must can't "begin" with a single step. a B
result:
a journeY oF,A thousanD 'mileS' musT can'T "begiN" witH A singlE steP. A b

PHP编程source:
A journey of,a thousand 'miles' must can't "begin" with a single step. a b'
result:
a journeY oF,A thousanD 'mileS' musT can'T "begiN" witH A singlE steP. A B'

PHP编程source:
A journey of,a thousand 'miles' must can't "begin" with a single step. a B"
result:
a journeY oF,A thousanD 'mileS' musT can'T "begiN" witH A singlE steP. A b"

PHP编程希望本文所述对大家的PHP程序设计有所赞助.

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