PHP实现模仿socket请求返回页面的方法

<?php
?$url = "www.XXXX.com";　　//自己做替换
?$parse = parse_url($url);　　//对URL进行解析,返回起组成部分.
?$host = $parse['host'];
?$path = $parse['path'];
?$port = 80;
?$timeout = 80;
?$fp = @fsockopen($host,$port,$errno,$errstr,$timeout);　　//打开socket链接
?if (!$fp){
???? echo $errno."--".$errstr;　　//如果错误,则返回错误代码和错误信息
?} else {
???? $out = "POST $path HTTP/1.1rn";　　//以下是HTTP哀求头信息
???? $out .= "Host: ".$host."rn";
???? $out .= "Accept: */*rn";
???? $out .= "Connection: Closern";
???? $out .= "Cookie: $cookiernrn";
???
???? @fwrite($fp,$out);　　//把哀求信息写到链接中
???? $status = stream_get_meta_data($fp);
???? if(!$status['timed_out']) {????
???????????????? while (!feof($fp)) {?
???????????????????? if(($header = @fgets($fp)) && ($header == "rn" ||? $header == "n")) {????
???????????????????????? break;????
???????????????????? }????
???????????????? }????
????????
???????????????? $stop = false;????
???????????????? while(!feof($fp) && !$stop) {????
???????????????????? $data = fread($fp,8192);????? //8192为可返回字节数
???????????????????? $return .= $data;????????
???????????????? }????
???????????? }????
???? fclose($fp);
???? print_r($return);
?}