如何让CI框架支持service层
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《：如何让CI框架支持service层》要点： 大家知道CodeIgniter框架式MVC分层的,通常大家把业务逻辑写到Controller中,而Model只负责和数据库打交道.PHP实战 但是随着业务越来越复杂,controller越来越臃肿,举一个简单的例子,比如说用户下订单,这必然会有一系列的操作：更新购物车、添加订单记录、会员添加积分等等,且下订单的过程可能在多种场景出现,如果这样的代码放controller中则很臃肿难以复用,如果放model会让持久层和业务层耦合.现在公司的项目就是,很多人将一些业务逻辑写到model中去了,model中又调其它model,也就是业务层和持久层相互耦合.这是极其不合理的,会让model难以维护,且办法难以复用.PHP实战 是不是可以考虑在controller和model中加一个业务层service,由它来负责业务逻辑,封装好的调用接口可以被controller复用.PHP实战 这样各层的任务就明确了： 基于上面描述,实现过程：
代码如下:
<?php class MY_Service { ??? public function __construct() ??? { ??????? log_message('debug',"Service Class Initialized"); ??? } ??? function __get($key) ??? { ??????? $CI = & get_instance(); ??????? return $CI->$key; ??? } } (2)扩展CI_Loader实现,加载service,在application/core下新建MY_Loader.php文件：PHP实战
代码如下:
<?php class MY_Loader extends CI_Loader { ??? /** ? * List of loaded sercices ? * ? * @var array ? * @access protected ? */ ?protected $_ci_services = array(); ?/** ? * List of paths to load sercices from ? * ? * @var array ? * @access protected ? */ ?protected $_ci_service_paths??= array(); ??? /** ???? * Constructor ???? * ???? * Set the path to the Service files ???? */ ??? public function __construct() ??? { ??????? parent::__construct(); ??????? $this->_ci_service_paths = array(APPPATH); ??? } ??? /** ???? * Service Loader ???? * ???? * This function lets users load and instantiate classes. ? * It is designed to be called from a user's app controllers. ? * ? * @param?string?the name of the class ? * @param?mixed?the optional parameters ? * @param?string?an optional object name ? * @return?void ???? */ ??? public function service($service = '',$params = NULL,$object_name = NULL) ??? { ??????? if(is_array($service)) ??????? { ??????????? foreach($service as $class) ??????????? { ??????????????? $this->service($class,$params); ??????????? } ??????????? return; ??????? } ??????? if($service == '' or isset($this->_ci_services[$service])) { ??????????? return FALSE; ??????? } ??????? if(! is_null($params) && ! is_array($params)) { ??????????? $params = NULL; ??????? } ??????? $subdir = ''; ??????? // Is the service in a sub-folder? If so,parse out the filename and path. ??????? if (($last_slash = strrpos($service,'/')) !== FALSE) ??????? { ??????????????? // The path is in front of the last slash ??????????????? $subdir = substr($service,$last_slash + 1); ??????????????? // And the service name behind it ??????????????? $service = substr($service,$last_slash + 1); ??????? } ??????? foreach($this->_ci_service_paths as $path) ??????? { ??????????? $filepath = $path .'service/'.$subdir.$service.'.php'; ??????????? if ( ! file_exists($filepath)) ??????????? { ??????????????? continue; ??????????? } ??????????? include_once($filepath); ??????????? $service = strtolower($service); ??????????? if (empty($object_name)) ??????????? { ??????????????? $object_name = $service; ??????????? } ??????????? $service = ucfirst($service); ??????????? $CI = &get_instance(); ??????????? if($params !== NULL) ??????????? { ??????????????? $CI->$object_name = new $service($params); ??????????? } ??????????? else ??????????? { ??????????????? $CI->$object_name = new $service(); ??????????? } ??????????? $this->_ci_services[] = $object_name; ??????????? return; ??????? } ??? } } (3)简单例子实现：
代码如下:
<?php class User extends CI_Controller { ??? public function __construct() ??? { ?? ??????? parent::__construct(); ??????? $this->load->service('user_service'); ??? } ??? public function login() ??? { ??????? $name = 'phpddt.com'; ??????? $psw = 'password'; ??????? print_r($this->user_service->login($name,$psw)); ??? } } service中调用model ：PHP实战
代码如下:
<?php class User_service extends MY_Service { ??? public function __construct() ??? { ??????? parent::__construct(); ??????? $this->load->model('user_model'); ??? } ??? public function login($name,$password) ??? { ??????? $user = $this->user_model->get_user_by_where($name,$password); ??????? //..... ??????? //..... ??????? //..... ??????? return $user; ??? } } model中你只跟db打交道：PHP实战
代码如下:
<?php class User_model extends CI_Model { ??? public function __construct() ??? { ??????? parent::__construct(); ??? } ??? public function get_user_by_where($name,$password) ??? { ??????? //$this->db ??????? //...... ??????? //...... ??????? return array('id' => 1,'name' => 'mckee'); ??? } } 基本实现思路便是这样的.PHP实战 编程之家培训学院每天发布《：如何让CI框架支持service层》等实战技能，PHP、MYSQL、LINUX、APP、JS,CSS全面培养人才。 （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |