如何在php中组合连续的月份名称？

发布时间：2020-12-13 22:49:22 所属栏目：PHP教程来源：网络整理

导读：我有一个像这样的数组： Array( [0] = Jan [1] = Feb [2] = Mar [3] = Apr [4] = May [5] = Jun [6] = Sep [7] = Oct [8] = Dec) 我需要将其转换为 Array( [0] = "Jan - Jun" [1] = "Sep - Oct" [2] = "Dec") 这几个月总是有序的,但由于阵列是动态的,我想不

我有一个像这样的数组：

Array
(
    [0] => Jan
    [1] => Feb
    [2] => Mar
    [3] => Apr
    [4] => May
    [5] => Jun
    [6] => Sep
    [7] => Oct
    [8] => Dec
)

我需要将其转换为

Array
(
    [0] => "Jan - Jun"
    [1] => "Sep - Oct"
    [2] => "Dec"
)

这几个月总是有序的,但由于阵列是动态的,我想不出一个有效的方法,除了将每个月转换为使用date_parse的数字,然后结合它周围的月份！但我真的很困惑如何做到这一点,任何想法？

解决方法

这样的事情怎么样：

function findConsecutiveMonths(array $input) {
    // Utility list of all months
    static $months = array('Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec');

    $chunks = array();

    for ($i = 0; $i < 12; $i++) {
        // Wait until the $i-th month is contained in the array
        if (!in_array($months[$i],$input)) {
            continue;
        }

        // Find first consecutive month that is NOT contained in the array
        for ($j = $i + 1; $j < 12; $j++) {
            if (!in_array($months[$j],$input)) {
                break;
            }
        }

        // Chunk is from month $i to month $j - 1
        $chunks[] = ($i == $j - 1) ? $months[$i] : $months[$i] .' - '. $months[$j - 1];

        // We know that month $j is not contained in the array so we can set $i
        // to $j - the search for the next chunk is then continued with month
        // $j + 1 because $i is incremented after the following line
        $i = $j;
    }

    return $chunks;
}

演示：http://codepad.viper-7.com/UfaNfH

（编辑：李大同）

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