在纯PHP5中创建MySQL转储

现在我正在使用：

<?php
include("config.php");

/* Misc */
$pathtobackup = realpath('.');
$backupfolder = realpath("backup");
$sqlfilename = "SQLDUMP-".date("d-m-Y--H-i").".sql";
$backupfilename = "BACKUP-".date("d-m-Y--H-i").".zip";
$backupfilepath = $backupfolder."/".$backupfilename;

/* Systemcall */
exec("/usr/bin/mysqldump -u{$mysqluser} -p{$mysqlpw} -h {$mysqlserver} {$mysqldb}",$sqldata,$fp);

$sqldump = implode("n",$sqldata);

if ($fp!=0){
    die("could not create mysql dumpn");
}

/* Create Zip */
$zip = new ZipArchive();

if ($zip->open($backupfilepath,ZIPARCHIVE::CREATE)!==TRUE) {
    die("cannot open <{$backupfilepath}>n");
}


$path = realpath('.');

$iterator  = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($pathtobackup,FilesystemIterator::SKIP_DOTS));

foreach($iterator as $name=>$object){

    $zip->addFile($name);

}

$zip->addFromString($sqlfilename,$sqldump);

if ($zip->close()!==TRUE) {
    die("cannot write <{$backupfilepath}>n");
}

?>

但是我想用纯PHP创建MySQL Dump以使其更兼容并且能够在其他服务器上使用它,在那里无法使用系统和mysqldump.

我希望你知道一个使用150文件库的解决方案:)

问候,
弗雷德里克