如何在PHP中更容易地将整数值映射到字符串？

发布时间：2020-12-13 22:15:15 所属栏目：PHP教程来源：网络整理

导读：如何重新考虑以下代码以使其更简洁,更易于维护？ if ($row['vocation'] == 1) $vocation = "sorcerer";if ($row['vocation'] == 2) $vocation = "druid";if ($row['vocation'] == 3) $vocation = "paladin";if ($row['vocation'] == 4) $vocation = "knight"

如何重新考虑以下代码以使其更简洁,更易于维护？

if ($row['vocation'] == 1) $vocation = "sorcerer";
if ($row['vocation'] == 2) $vocation = "druid";
if ($row['vocation'] == 3) $vocation = "paladin";
if ($row['vocation'] == 4) $vocation = "knight";

if ($row['vocation'] == 5) $vocation = "master sorcerer";
if ($row['vocation'] == 6) $vocation = "elder druid";
if ($row['vocation'] == 7) $vocation = "royal paladin";
if ($row['vocation'] == 8) $vocation = "elite knight";
else $vocation = "none";

解决方法

我建议使用一个数组,如下所示：

static $vocations = array(
  1 => 'sorceror',2 => 'druid',3 => 'paladin',4 => 'knight',5 => 'master sorceror',6 => 'elder druid',7 => 'royal paladin',8 => 'elite knight',);

$vocation = 
  isset($vocations[$row['vocation']]) ? $vocations[$row['vocation']] : 'none';

（编辑：李大同）

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