php – 将使用循环创建的数组附加到另??一个数组
发布时间:2020-12-13 22:04:38 所属栏目:PHP教程 来源:网络整理
导读:我有一个阵列 $variables_a = array( 'a' = $a,'b' = $b,'c' = $c); 然后另一个$variables_b = array(‘x’,’y’,’z’)我想循环遍历B数组,如下所示: foreach($variables_b as $var) { $variables_c[] = array($var = $$var);} 然后合并A C和$variables_co
我有一个阵列
$variables_a = array( 'a' => $a,'b' => $b,'c' => $c ); 然后另一个$variables_b = array(‘x’,’y’,’z’)我想循环遍历B数组,如下所示: foreach($variables_b as $var) { $variables_c[] = array($var => $$var); } 然后合并A& C和$variables_combined = array_merge($variables_A,$variables_C) 我希望得到的输出是我print_r的时候 Array ( [a] => a [b] => b [c] => c [x] => x [y] => y [z] => z ) 但我得到的是 Array ( [a] => a [b] => b [c] => c [0] => Array ( [x] => x ) [1] => Array ( [y] => y ) [2] => Array ( [z] => z ) ) 如果我将$feature_variables [] = array($feature => $$功能)更改为$feature_variables = array($feature => $$功能),我会得到 Array ( [a] => a [b] => b [c] => c [z] => z ) 即$variables_b中的最后一项,但没有其他项.那我哪里错了? 解决方法
请循环遍历数组c,如:
foreach($variables_b as $var) { $variables_c[$var] = $$var; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |