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php – 将索引数组转换为键匹配的单独数组

发布时间:2020-12-13 21:57:38 所属栏目:PHP教程 来源:网络整理
导读:我认为我的问题很容易解决,但对于我的生活,我无法弄清楚. 我需要转换这个多维数组: [additionallocations] = Array ( [Address] = Array ( [0] = Address1 [1] = Address2 ) [City] = Array ( [0] = City1 [1] = City2 ) [State] = Array ( [0] = AK [1] =
我认为我的问题很容易解决,但对于我的生活,我无法弄清楚.

我需要转换这个多维数组:

[additionallocations] => Array
        (
            [Address] => Array
                (
                    [0] => Address1
                    [1] => Address2
                )

            [City] => Array
                (
                    [0] => City1
                    [1] => City2
                )

            [State] => Array
                (
                    [0] => AK
                    [1] => DC
                )

            [Zip] => Array
                (
                    [0] => 234423
                    [1] => 32423
                )

            [Country] => Array
                (
                    [0] => US
                    [1] => US
                )

        )

进入:

[additionallocations0] => Array
        (
           [Address] => Address1
           [City] => City1
           [State] => AK
           [Zip] => 234423
           [Country] => US
        )
[additionallocations1] => Array 
        (
           [Address] => Address2
           [City] => City2
           [State] => DC
           [Zip] => 32423
           [Country] => US
         )

我尝试过使用foreach循环但是我无法得到预期的结果:

$count = 0;
        foreach($_POST['additionallocations'] as $value => $key) {
            foreach($key as $row) {
                $additional['additional'.$count] = array($value => $row);
            }
            $count++;
        }

这是一个phpfiddle我需要将$locationsBAD数组转换为$locationsGOOD数组

解决方法

Ofir缺少位置计数值.

以下是我解决您问题的方法:

<?php
// we need to know how many locations beforehand
$qty = count($additionallocations["Address"]);

for ($l=0; $l<$qty; $l++)
{
    foreach($additionallocations as $param => $values)
    {
        $new_locations['location'.$l][$param] = $values[$l];
    }
}
print_r($new_locations);
?>

我得到:

Array
(
    [location0] => Array
        (
            [Address] => Address1
            [City] => City1
            [State] => AK
            [Zip] => 234423
            [Country] => US
        )

    [location1] => Array
        (
            [Address] => Address2
            [City] => City2
            [State] => DC
            [Zip] => 32423
            [Country] => US
        )

)

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