php – 将索引数组转换为键匹配的单独数组
发布时间:2020-12-13 21:57:38 所属栏目:PHP教程 来源:网络整理
导读:我认为我的问题很容易解决,但对于我的生活,我无法弄清楚. 我需要转换这个多维数组: [additionallocations] = Array ( [Address] = Array ( [0] = Address1 [1] = Address2 ) [City] = Array ( [0] = City1 [1] = City2 ) [State] = Array ( [0] = AK [1] =
我认为我的问题很容易解决,但对于我的生活,我无法弄清楚.
我需要转换这个多维数组: [additionallocations] => Array ( [Address] => Array ( [0] => Address1 [1] => Address2 ) [City] => Array ( [0] => City1 [1] => City2 ) [State] => Array ( [0] => AK [1] => DC ) [Zip] => Array ( [0] => 234423 [1] => 32423 ) [Country] => Array ( [0] => US [1] => US ) ) 进入: [additionallocations0] => Array ( [Address] => Address1 [City] => City1 [State] => AK [Zip] => 234423 [Country] => US ) [additionallocations1] => Array ( [Address] => Address2 [City] => City2 [State] => DC [Zip] => 32423 [Country] => US ) 我尝试过使用foreach循环但是我无法得到预期的结果: $count = 0; foreach($_POST['additionallocations'] as $value => $key) { foreach($key as $row) { $additional['additional'.$count] = array($value => $row); } $count++; } 这是一个phpfiddle我需要将$locationsBAD数组转换为$locationsGOOD数组 解决方法
Ofir缺少位置计数值.
以下是我解决您问题的方法: <?php // we need to know how many locations beforehand $qty = count($additionallocations["Address"]); for ($l=0; $l<$qty; $l++) { foreach($additionallocations as $param => $values) { $new_locations['location'.$l][$param] = $values[$l]; } } print_r($new_locations); ?> 我得到: Array ( [location0] => Array ( [Address] => Address1 [City] => City1 [State] => AK [Zip] => 234423 [Country] => US ) [location1] => Array ( [Address] => Address2 [City] => City2 [State] => DC [Zip] => 32423 [Country] => US ) ) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |