如何将POSTMAN中的数据转换为PHP Curl Request?
发布时间:2020-12-13 21:56:26 所属栏目:PHP教程 来源:网络整理
导读:我有邮递员的API.我想创建一个CURL请求并获得适当的响应.这是我的POSTMAN API. 我成功地得到了这个回应. "{"Request":{"state":"Manama","address":"406 Falcon Tower","address2":"Diplomatic Area","city":"Manama","country":"BH",
我有邮递员的API.我想创建一个CURL请求并获得适当的响应.这是我的POSTMAN API.
我成功地得到了这个回应. "{"Request":{"state":"Manama","address":"406 Falcon Tower","address2":"Diplomatic Area","city":"Manama","country":"BH","fullname":"Dawar Khan","postal":"317"},"Response":{"status":"Success","code":100,"message":"Address is verified"}}" 现在我想在我的PHP代码中使用这个API调用.我用过这段代码. $data = array( 'Request' => 'ValidateAddress','address' => test_input($form_data->address),'secondAddress' => test_input($form_data->secondAddress),'city' => test_input($form_data->city),'country' => test_input($form_data->country),'name' => test_input($form_data->name),'zipCode' => test_input($form_data->zipCode),'merchant_id' => 'shipm8','hash' => '09335f393d4155d9334ed61385712999' ); $data_string = json_encode($data); $url = 'myurl.com/'; $ch = curl_init($url); curl_setopt($ch,CURLOPT_CUSTOMREQUEST,"POST"); curl_setopt($ch,CURLOPT_POSTFIELDS,$data_string); curl_setopt($ch,CURLOPT_RETURNTRANSFER,true); curl_setopt($ch,CURLOPT_HTTPHEADER,array( 'Content-Type: application/json','Content-Length: ' . strlen($data_string)) ); $result = curl_exec($ch); curl_close($ch); $json_result = json_decode($result,true); echo '<pre>';print_r($json_result);echo '</pre>'; 但我看不到我的$json_result.它只是回应< pre>< / pre>在视图中.谁能指导我?提前致谢.我想得到我的回复. UPDATE 我使用了curl_error,它给了我以下错误.
解决方法
根据更新的问题更新答案.
有两种方法可以解决这个问题 冗长,耗时但干净 >在Web浏览器中访问URL. curl_setopt($ch,CURLOPT_SSL_VERIFYPEER,true); curl_setopt($ch,CURLOPT_SSL_VERIFYHOST,2); curl_setopt($ch,CURLOPT_CAINFO,getcwd() . "/CAcerts/BuiltinObjectToken-EquifaxSecureCA.crt"); 快但脏 curl_setopt($ch,false); 我们正在配置cURL以接受任何服务器(对等)证书.从安全角度来看,这不是最佳选择. 摘录自very detailed and precise article的截图,以便更好地理解.请在生产现场实际实施之前参考相同的内容. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |