如何根据php中的特定值将数组拆分为子数组
发布时间：2020-12-13 21:40:26 所属栏目：PHP教程 来源：网络整理
导读：我有一个如下所示的数组,我想做的是,基于datepart创建多个数组,如(2011-02-04)： Array( [0] = Array ( [avgvalue] = 0 [maxvalue] = 0 [minvalue] = 0 [nrsamples] = 0 [stddeviation] = 0 [timestamp] = 2011-02-04T11:00:00.000Z ) [1] = Array ( [avgval
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我有一个如下所示的数组,我想做的是,基于datepart创建多个数组,如(2011-02-04)：
Array
(
[0] => Array
(
[avgvalue] => 0
[maxvalue] => 0
[minvalue] => 0
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-04T11:00:00.000Z
)
[1] => Array
(
[avgvalue] => 268.3
[maxvalue] => 268.3
[minvalue] => 268.3
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-04T12:00:00.000Z
)
[2] => Array
(
[avgvalue] => 268.391666667
[maxvalue] => 268.4
[minvalue] => 268.3
[nrsamples] => 0.0288675134595
[stddeviation] => 0.0288675134595
[timestamp] => 2011-02-04T13:00:00.000Z
)
[3] => Array
(
[avgvalue] => 268.433333333
[maxvalue] => 268.5
[minvalue] => 268.4
[nrsamples] => 0.0492365963918
[stddeviation] => 0.0492365963918
[timestamp] => 2011-02-04T14:00:00.000Z
)
[4] => Array
(
[avgvalue] => 268.5
[maxvalue] => 268.5
[minvalue] => 268.5
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-04T15:00:00.000Z
)
[5] => Array
(
[avgvalue] => 268.575
[maxvalue] => 268.6
[minvalue] => 268.5
[nrsamples] => 0.0452267016867
[stddeviation] => 0.0452267016867
[timestamp] => 2011-02-04T16:00:00.000Z
)
[6] => Array
(
[avgvalue] => 268.616666667
[maxvalue] => 268.7
[minvalue] => 268.6
[nrsamples] => 0.0389249472081
[stddeviation] => 0.0389249472081
[timestamp] => 2011-02-04T17:00:00.000Z
)
[7] => Array
(
[avgvalue] => 268.7
[maxvalue] => 268.7
[minvalue] => 268.7
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-04T18:00:00.000Z
)
[8] => Array
(
[avgvalue] => 268.741666667
[maxvalue] => 268.8
[minvalue] => 268.7
[nrsamples] => 0.0514928650545
[stddeviation] => 0.0514928650545
[timestamp] => 2011-02-04T19:00:00.000Z
)
[9] => Array
(
[avgvalue] => 268.8
[maxvalue] => 268.8
[minvalue] => 268.8
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-04T20:00:00.000Z
)
[10] => Array
(
[avgvalue] => 268.883333333
[maxvalue] => 268.9
[minvalue] => 268.8
[nrsamples] => 0.0389249472081
[stddeviation] => 0.0389249472081
[timestamp] => 2011-02-04T21:00:00.000Z
)
[11] => Array
(
[avgvalue] => 268.908333333
[maxvalue] => 269
[minvalue] => 268.9
[nrsamples] => 0.0288675134595
[stddeviation] => 0.0288675134595
[timestamp] => 2011-02-04T22:00:00.000Z
)
[12] => Array
(
[avgvalue] => 269
[maxvalue] => 269
[minvalue] => 269
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-04T23:00:00.000Z
)
[13] => Array
(
[avgvalue] => 269.05
[maxvalue] => 269.1
[minvalue] => 269
[nrsamples] => 0.0522232967867
[stddeviation] => 0.0522232967867
[timestamp] => 2011-02-05T00:00:00.000Z
)
[14] => Array
(
[avgvalue] => 269.1
[maxvalue] => 269.1
[minvalue] => 269.1
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-05T01:00:00.000Z
)
[15] => Array
(
[avgvalue] => 269.166666667
[maxvalue] => 269.2
[minvalue] => 269.1
[nrsamples] => 0.0492365963917
[stddeviation] => 0.0492365963917
[timestamp] => 2011-02-05T02:00:00.000Z
)
[16] => Array
(
[avgvalue] => 269.2
[maxvalue] => 269.2
[minvalue] => 269.2
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-05T03:00:00.000Z
)
[17] => Array
(
[avgvalue] => 269.291666667
[maxvalue] => 269.3
[minvalue] => 269.2
[nrsamples] => 0.0288675134595
[stddeviation] => 0.0288675134595
[timestamp] => 2011-02-05T04:00:00.000Z
)
[18] => Array
(
[avgvalue] => 269.333333333
[maxvalue] => 269.4
[minvalue] => 269.3
[nrsamples] => 0.0492365963917
[stddeviation] => 0.0492365963917
[timestamp] => 2011-02-05T05:00:00.000Z
)
[19] => Array
(
[avgvalue] => 269.4
[maxvalue] => 269.4
[minvalue] => 269.4
[nrsamples] => 0
[stddeviation] => 0
[timestamp] => 2011-02-05T06:00:00.000Z
)
)
以上列表是数组.它有时间戳键,我爆炸了时间戳键,以便我得到日期和时间部分分离,现在我有问题将数组拆分成子数组.我想要的是2011-02-04有一个数组(包含该日期的所有值)和2011-02-05的另一个数组(包含所有那个日期的值).这可以是动态的,我的意思是日期可以更多.那么,我该怎么做呢. 我想要它： array[0] => array(... list of all the values for 2011-02-04),array[1] => array(...list of all values for 2011-02-05) 被困在这里,无法使它发挥作用.请建议. 解决方法
假设所有条目(它看起来都是)的日期格式相同,您可以简单地循环遍历数组：
$result = array();
foreach($array as $item) {
$date = strstr($item['timestamp'],'T',true);
if(!array_key_exists($date,$result)) {
$result[$date] = array();
}
$result[$date][] = $item;
}
参考： 根据原始数组中项目的顺序,您可能必须使用 （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |