php – 使用列标题将CSV处理为数组
发布时间:2020-12-13 21:28:40 所属栏目:PHP教程 来源:网络整理
导读:我有一个CSV,第一行包含字段名称.示例数据是…… "Make","Model","Note""Chevy","1500","loaded""Chevy","2500","""Chevy","","loaded" 我需要在键值对数组中格式化我的数据,其中键名是列标题.我猜对于第1行它会是这样的: $array = [ "Make" = "Chevy","Mod
我有一个CSV,第一行包含字段名称.示例数据是……
"Make","Model","Note" "Chevy","1500","loaded" "Chevy","2500","" "Chevy","","loaded" 我需要在键值对数组中格式化我的数据,其中键名是列标题.我猜对于第1行它会是这样的: $array = [ "Make" => "Chevy","Model" => "1500","Note" => "loaded" ]; ……排2 … $array = [ "Make" => "Chevy","Note" => "" ]; ……和第3行…… $array = [ "Make" => "Chevy","Model" => "","Note" => "loaded" ]; 我不确定除了静态之外该怎么做 – 问题是带有相关数据的列可能会从一个文件更改为下一个…重新排列,删除或添加的列. 你的想法非常感谢. 解决方法$all_rows = array(); $header = fgetcsv($file); while ($row = fgetcsv($file)) { $all_rows[] = array_combine($header,$row); } print_r($all_rows); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |