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[LeetCode 205]Isomorphic Strings

发布时间:2020-12-13 20:45:06 所属栏目:PHP教程 来源:网络整理
导读:题目链接:isomorphic-strings Given two strings s and t ,determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t . All occurrences of a character must be replaced with another character w

题目链接:isomorphic-strings


Given two strings s and t,determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add",return true.

Given "foo",244)">"bar",return false.

"paper",244)">"title",sans-serif; font-size:14px; line-height:30px"> Note:
You may assume both s and t have the same length.


// 29 / 29 test cases passed. // Status: Accepted // Runtime: 390 ms // Submitted: 1 minute ago public class Solution { public boolean isIsomorphic(String s,String t) { Map<Character,Character> sm = new HashMap<Character,Character>(); Map<Character,Character> tm = new HashMap<Character,Character>(); for (int i = 0; i < s.length(); i++) { char char_s = s.charAt(i); char char_t = t.charAt(i); if(sm.get(char_s) == null) { if(tm.get(char_t) == null) { sm.put(char_s,char_t); tm.put(char_t,char_s); } else return false; } else { if(tm.get(char_t) == null) return false; if(!(sm.get(char_s) == char_t && tm.get(char_t) == char_s)) return false; } } return true; } }


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