as easy problem

发布时间：2020-12-13 20:45:01 所属栏目：PHP教程来源：网络整理

导读：Time Limit: 1000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 16297Accepted Submission(s): 10937 Problem Description we define f(A) = 1,f(a) = ⑴,f(B) = 2,f(b) = ⑵,... f(Z) = 26,f(z) = ⑵6; Give you

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 16297 Accepted Submission(s): 10937

Problem Description

we define f(A) = 1,f(a) = ⑴,f(B) = 2,f(b) = ⑵,... f(Z) = 26,f(z) = ⑵6;
Give you a letter x and a number y,you should output the result of y+f(x).

Input

On the first line,contains a number T.then T lines follow,each line is a case.each case contains a letter and a number.

Output

for each case,you should the result of y+f(x) on a line.

Sample Input

6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output

#include<stdio.h>

main()
{
char c;
int a,b,d,s,n,w,i,q;
scanf("%d",&q);
getchar();
//while(n--)
for(i=0;i<q;i++)
{
scanf("%c%d",&c,&s);
if(c>='A'&&c<='Z')
{a=c-'0'⑴6;
w=a+s;
//printf("%d ",w);
}
//continue;
if(c>='a'&&c<='z')
{b=c-'0';
b=b⑷8;
a=-b;
w=a+s;
//printf("%d ",w);
//continue;
}
printf("%d ",w);
getchar();
}

return 0;
}

（编辑：李大同）

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