158A - Next Round

发布时间：2020-12-13 20:22:31 所属栏目：PHP教程来源：网络整理

导读：A. Next Round time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Contestant who earns a score equal to or greater than the k -th place finisher's score will advance to the next rou

"Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round,as long as the contestant earns a positive score..." ― an excerpt from contest rules.

A total of n participants took part in the contest (n?≥?k),and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1?≤?k?≤?n?≤?50) separated by a single space.

The second line contains n space-separated integers a1,?a2,?...,?an (0?≤?ai?≤?100),where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is,for all i from 1 to n?-?1 the following condition is fulfilled: ai?≥?ai?+?1).

Output

Output the number of participants who advance to the next round.

Sample test(s)

input
8 5
10 9 8 7 7 7 5 5

output
6

input
4 2
0 0 0 0

output
0

Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points,there are 6 advancers.

In the second example nobody got a positive score.

import java.util.*; public class Main { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); int k=sc.nextInt(); int count=0; int[] score = new int[60]; for(int i=0;i<n;i++) score[i]=sc.nextInt(); int max=score[k⑴]; for(int i=0;i<n;i++) if(score[i]>=max&&score[i]>0) count++; System.out.println(count); } }

（编辑：李大同）

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