php – 如何使用Yii 2 ActiveRecord进行IS NULL和IS NOT NULL？

我在search()方法中有另一个[gii-generated]搜索模型,其配置如下：

public function search($params)
{
    $query = User::find();

    // add conditions that should always apply here

    $this->load($params);

    if (!$this->validate()) {
        // uncomment the following line if you do not want to return any records when validation fails
        // $query->where('0=1');
        return $dataProvider;
    }

    $andFilterWhere = [
        'id' => $this->id,'status' => $this->status,'role' => $this->role,'created_at' => $this->created_at,'updated_at' => $this->updated_at,'completed_files' => $this->completed_files,// 'activated_at' => null,];

    if(!isset($_GET['deleted'])) {
        $query->where(['deleted_at' => null]);
        $andFilterWhere['deleted_at'] = null;
    } else if($_GET['deleted'] === 'true') {
        $query->where(['not',['deleted_at' => null]]);
    }

    // grid filtering conditions
    $query->andFilterWhere(
        $andFilterWhere
    );

    $query->andFilterWhere(['like','first_name',$this->username])
        ->andFilterWhere(['like','auth_key',$this->auth_key])
        ->andFilterWhere(['like','password_hash',$this->password_hash])
        ->andFilterWhere(['like','password_reset_token',$this->password_reset_token])
        ->andFilterWhere(['like','email',$this->email])
        ->andFilterWhere(['like',$this->first_name])
        ->andFilterWhere(['like','last_name',$this->last_name]);

    if($this->activated || $this->activated === "0") {
        #die(var_dump($this->activated));
        if($this->activated === '1') {
            // this doesn't filter
            $query->andFilterWhere(['not',['activated_at' => null]]);
        } else if($this->activated === '0') {
            // this doesn't either
            $query->andFilterWhere(['activated_at',null]);
        }
    }

    $dataProvider = new ActiveDataProvider([
        'query' => $query,]);

    return $dataProvider;
}

是的,我在我的班级中设置了激活的属性：

public $activated;

我的rules()方法如下：

public function rules()
{
    return [
        [['id','status','role','created_at','updated_at','completed_files'],'integer'],['activated','string'],[['username','deleted_at','completed_files','activated_at'],'safe'],];
}

我试图在search()方法中设置的是根据$activated值过滤字段activated_at(参见上面的代码)：

if($this->activated || $this->activated === "0") {
    #die(var_dump($this->activated));
    if($this->activated === '1') {
        // this doesn't filter
        $query->andFilterWhere(['not',['activated_at' => null]]);
    } else if($this->activated === '0') {
        // this doesn't either
        $query->andFilterWhere(['activated_at',null]);
        $andFilterWhere['activated_at'] = null;
    }
}

我将它与GridView一起使用 – 除了这个之外,其他每个过滤器都有效.

我在这做错了什么？

Aand如何正确地执行此类查询：

IS NULL something
IS NOT NULL something

使用Yii 2的ActiveRecord查询构建器？

编辑：行：if(！isset($_ GET [‘deleted’]))用于其他东西,这是正常的.