在PHP中构建来自多维数组的路径

发布时间：2020-12-13 17:50:11 所属栏目：PHP教程来源：网络整理

导读：我有一个数组,如： $tree = array( 'folder_1' = array( 'folder_1_1','folder_1_2' = array( 'folder_1_2_1','folder_1_2_2' ),'folder_1_3' ),'folder_2' = array( 'folder_2_1' = array( 'folder_2_1_1' = array( 'folder_2_1_1_1','folder_2_1_1_2' ) ),

我有一个数组,如：

$tree = array(
    'folder_1' => array(
        'folder_1_1','folder_1_2' => array(
            'folder_1_2_1','folder_1_2_2'
        ),'folder_1_3'
    ),'folder_2' => array(
        'folder_2_1' => array(
            'folder_2_1_1' => array(
                'folder_2_1_1_1','folder_2_1_1_2'
            )
        ),)
);

我正在尝试构建一个路径数组：

$paths = array(
    'folder_1','folder_1/folder_1_1','folder_1/folder_1_2','folder_1/folder_1_2/folder_1_2_1','folder_1/folder_1_2/folder_1_2_2','folder_2','folder_2/folder_2_1',...
);

我似乎无法找到实现这一目标的方法.我遇到的问题是文件夹名称可以是数组键,也可以是数组元素.

这是我到目前为止所做的,但我没有接近解决方案……

$paths = transform_tree_to_paths($trees);

function transform_tree_to_paths($trees,$current_path = '',$paths = array())
{

    if (is_array($trees)) {
        foreach ($trees as $tree => $children) {
            $current_path .= $tree . '/';
            return transform_tree_to_paths($children,$current_path,$paths);
        }
        $paths[] = $current_path;
        $current_path = '';
    } else {
        $paths[]  = $trees;
    }

    return $paths;
}

解决方法

这样的事怎么样？

function gen_path($tree,$parent=null) {
    $paths = array();

    //add trailing slash to parent if it is not null
    if($parent !== null) {
        $parent = $parent.'/';
    }

     //loop through the tree array
     foreach($tree as $k => $v) {
        if(is_array($v)) {
            $currentPath = $parent.$k;
            $paths[] = $currentPath;
            $paths = array_merge($paths,gen_path($v,$currentPath));
        } else {
            $paths[] = $parent.$v;
        }
    }

    return $paths;
}

你朝着正确的方向前进,但有点错过了标记.函数中的递归函数调用之前的return语句导致从不调用foreach循环之后的所有内容.

（编辑：李大同）

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