php – 在Facebook画布应用程序中,一旦我在登录中捕获它,我将在
发布时间:2020-12-13 17:45:20 所属栏目:PHP教程 来源:网络整理
导读:我正在使用 javascript sdk.在文档中,它表示您从响应对象获得FB.getLoginStatus()在用户状态=已连接时返回的签名请求,但现在我需要解析已签名的请求.如何将它发送到php页面我有解析代码?我是否在我的画布应用程序索引页面上包含php代码,然后将signedRequest
我正在使用
javascript sdk.在文档中,它表示您从响应对象获得FB.getLoginStatus()在用户状态=已连接时返回的签名请求,但现在我需要解析已签名的请求.如何将它发送到php页面我有解析代码?我是否在我的画布应用程序索引页面上包含php代码,然后将signedRequest发送到同一页面上的代码?或者将代码保存在单独的页面上并传递SR.
第一个代码块在我的index.html页面上.它检查登录状态并从响应对象获取签名的请求参数. 第二个块是php代码,用于解析签名请求,当你通过registratiton插件捕获它时,但当你提供url作为参数时,插件会自动将SR发送到这个页面.在画布应用程序中,我必须自己传递它.我怎么做? JavaScript的 FB.getLoginStatus(function(response) { if (response.status === 'connected') { // the user is logged in and has authenticated your // app,and response.authResponse supplies // the user's ID,a valid access token,a signed // request,and the time the access token // and signed request each expire var uid = response.authResponse.userID; var accessToken = response.authResponse.accessToken; var signedRequest = response.authResponse.signedRequest; } else if (response.status === 'not_authorized') { // the user is logged in to Facebook,} else { // the user isn't logged in to Facebook. } }); PHP页面 <?php define('FACEBOOK_APP_ID','3*****88&'); // Place your App Id here define('FACEBOOK_SECRET','1345*****eb4f2da'); // Place your App Secret Here // No need to change the function body function parse_signed_request($signed_request,$secret) { list($encoded_sig,$payload) = explode('.',$signed_request,2); // decode the data $sig = base64_url_decode($encoded_sig); $data = json_decode(base64_url_decode($payload),true); if (strtoupper($data['algorithm']) !== 'HMAC-SHA256') { error_log('Unknown algorithm. Expected HMAC-SHA256'); return null; } // check sig $expected_sig = hash_hmac('sha256',$payload,$secret,$raw = true); if ($sig !== $expected_sig) { error_log('Bad Signed JSON signature!'); return null; } return $data; } function base64_url_decode($input) { return base64_decode(strtr($input,'-_','+/')); } if ($_REQUEST) { $response = parse_signed_request($_REQUEST['signed_request'],FACEBOOK_SECRET); } $name = $response["registration"]["name"]; $email = $response["registration"]["email"]; $password = $response["registration"]["password"]; $uID = $response["user_id"]; ?> 解决方法
在
Clay’s Answer上扩展你可以用
jQuery.get()实现这样的东西:
var signed_request = getSignedRequest(),// however you do this.. url = "http://yoursite.com/phppage.php",// wherever your php code is ajax = $.get(url,{signed_request: signed_request}); // initiate ajax call // ajax success handler ajax.done(function(ajaxResponse){ console.log(ajaxResponse); }); 当然,您需要在PHP文件中获取该值 $signed_request = $_GET['signed_request']; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |