PHP – 计算多维数组中第一个元素的唯一值

发布时间：2020-12-13 17:26:22 所属栏目：PHP教程来源：网络整理

导读：我有这个数组： Array ( [0] = Array ( [0] = b [1] = d [2] = c [3] =a [4] = ) [1] = Array ( [0] = c [1] = a [2] = d [3] = [4] = ) [2] = Array ( [0] = b [1] = d [2] = a [3] = [4] = )[3] = Array ( [0] = a [1] = d [2] = c [3] =b [4] = )) 并且想

我有这个数组：

Array ( 
[0] => Array ( [0] => b [1] => d [2] => c [3] =>a [4] => ) 

[1] => Array ( [0] => c [1] => a [2] => d [3] => [4] => ) 

[2] => Array ( [0] => b [1] => d [2] => a [3] => [4] => )

[3] => Array ( [0] => a [1] => d [2] => c [3] =>b [4] => )

)

并且想要对每个内部数组的第一个元素中的唯一值执行计数.在上面的例子中,一个有b中的2个,c中的1个和a中的1个.

我测试了这个：

$count = 0;
foreach ($the_outer_array as $key=>$value) {
    if ($value [0] == 'c') {
        $count++;
    }
}

但我一次只能检查一个值.想知道是否有一个外循环,“foreach(范围(‘a’,’d’)为$i)”？计数完成后,我希望将值存储在一个数组中(即找到的字母和实例数).

循环遍历内循环中第一个元素的唯一值的任何建议？再一次谢谢你！

解决方法

使用 array_key_exists&递增计数,

$newArray = array();
foreach ($the_outer_array as $key=>$value) {
    $firstValue = $value[0];
    if ($foundKey = array_key_exists($firstValue,$newArray)) {
        $newArray[$firstValue] += 1;
    }
   else{
        $newArray[$firstValue] = 1;
   }
}

DEMO.

（编辑：李大同）

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