php – 数组键作为插入的mysql列名？

我正在使用一个将搜索结果作为json返回的API.然后,我需要将其写入MYSQL表.我以前成功完成了这个,但这次情况有所不同,我认为这是因为结果数组的结构：键名是动态的,如果没有特定键的数据,键不是在数组中列出.这是一个数组的示例vardump：

array
  0 => 
    array
      'title' => string 'Funny but not funny' (length=19)
      'body' => string 'by Daniel Doi-yesterday while eating at Curry House...
      'url' => string 'http://danieldoi.com/2012/11/20/funny-but-not-funny/' 
      'source_site_name' => string 'WordPress.com' (length=13)
      'source_site_url' => string 'http://www.wordpress.com' (length=24)
      'query_topic' => string 'thanksgiving' (length=12)
      'query_string' => string 'blogs=on&topic=thanksgiving&output=json' (length=39)
  1 => 
    array
      'title' => string 'Travel Easy this Holiday Season...' (length=34)
      'body' => string 'Give yourself a few gifts and get this holiday season off...
      'url' => string 'http://facadebeauty.wordpress.com/2012/11/20
      'date_published' => string 'Tue,20 Nov 2012 18:22:35 +0000' (length=31)
      'date_published_stamp' => string '1353435755' (length=10)

请注意密钥的顺序/包含如何变更.

我建议的解决方案是使用数组键作为列名,将它们变成一个变量以在查询语句中使用,但这对我不起作用.这是我的尝试：

$jsonString = file_get_contents("http://search-query-URL&output=json");
$array = json_decode($jsonString,true);

// database connection code snipped out here

$table = "results";

foreach($array as $arr_value) {
        foreach ($arr_value as $value) {
          $colName = key($arr_value);
          $colValue = ($value);
          $insert="INSERT INTO $table ($colName) VALUES ('$colValue')";

          mysql_query($insert) OR die(mysql_error());
          next($arr_value);
              }
         }

关于下一步要去哪里的建议？谢谢！

更新11/27：

在这里,我试图适应大卫的建议.我收到以下错误：“数据库连接错误(1110)列’标题’在查询时指定了两次.”

这是我现在的代码：

$mysqli = mysqli_connect("localhost");
mysqli_select_db($mysqli,"mydatabase");

foreach ($array as $column) {
    foreach ($column as $key => $value) {
    $cols[] = $key;
    $vals[] = mysqli_real_escape_string($mysqli,$value);
    }
}

$colnames = "`".implode("`,`",$cols)."`";
$colvals = "'".implode("','",$vals)."'";
$mysql = mysqli_query($mysqli,"INSERT INTO $table ($colnames) VALUES ($colvals)") or die('Database Connection Error ('.mysqli_errno($mysqli).') '.mysqli_error($mysqli). " on query: INSERT INTO $table ($colnames) VALUES ($colvals)");
mysqli_close($mysqli);
if ($mysql)
return TRUE;
else return FALSE;

最后的升级 – 工作！

它正在发挥作用.这是我们得到的：

$mysqli = mysqli_connect("localhost");
mysqli_select_db($mysqli,"mydatabase");
  foreach ($array as $column) {
foreach ($column as $key => $value) {
    $cols[] = $key;
    $vals[] = mysqli_real_escape_string($mysqli,$value);
    }
  $colnames = "`".implode("`,$cols)."`";
  $colvals = "'".implode("',$vals)."'";
  $mysql = mysqli_query($mysqli,"INSERT INTO $table ($colnames) VALUES ($colvals)") or die('Database Connection Error ('.mysqli_errno($mysqli).') '.mysqli_error($mysqli). " on query: INSERT INTO $table ($colnames) VALUES ($colvals)");

  unset($cols,$vals);
}
  mysqli_close($mysqli);
if ($mysql)
return TRUE;
else return FALSE;

function mysqli_insert($table,$assoc) {
    $mysqli = mysqli_connect(PUT YOUR DB CREDENTIALS HERE);
    mysqli_select_db($mysqli,DATABASE NAME HERE);
    foreach ($assoc as $column => $value) {
        $cols[] = $column;
        $vals[] = mysqli_real_escape_string($mysqli,$value);
    }
    $colnames = "`".implode("`,$cols)."`";
    $colvals = "'".implode("',$vals)."'";
    $mysql = mysqli_query($mysqli,"INSERT INTO $table ($colnames) VALUES ($colvals)") or die('Database Connection Error ('.mysqli_errno($mysqli).') '.mysqli_error($mysqli). " on query: INSERT INTO $table ($colnames) VALUES ($colvals)");
    mysqli_close($mysqli);
    if ($mysql)
        return TRUE;
    else return FALSE;
}