php – Mandrill提供无效的应用程序密钥错误
发布时间:2020-12-13 17:19:08 所属栏目:PHP教程 来源:网络整理
导读:我只想尝试将mandrill邮件发送到我的应用程序下面是我在php中的代码 $args = array( 'key' = '73357ad2-e59e-4669---------','message' = array( "html" = "prntHi Adam,/prnprntThanks for a href="http://mandrill.com"registering/a./prnpetc
我只想尝试将mandrill邮件发送到我的应用程序下面是我在php中的代码
$args = array( 'key' => '73357ad2-e59e-4669---------','message' => array( "html" => "<p>rntHi Adam,</p>rn<p>rntThanks for <a href="http://mandrill.com">registering</a>.</p>rn<p>etc etc</p>","text" => null,"from_email" => "xxx@xxx.com","from_name" => "SIVOnline","subject" => "Your recent registration","to" => array(array("email" => "xxx@xxx.com")),"track_opens" => true,"track_clicks" => true,"auto_text" => true ) ); // Open a curl session for making the call $curl = curl_init('https://mandrillapp.com/api/1.0/messages/send.json' ); // Tell curl to use HTTP POST curl_setopt($curl,CURLOPT_POST,true); curl_setopt($curl,CURLOPT_SSL_VERIFYPEER,false); // Tell curl not to return headers,but do return the response curl_setopt($curl,CURLOPT_HEADER,false); curl_setopt($curl,CURLOPT_RETURNTRANSFER,CURLOPT_HTTPHEADER,array('Content-Type: application/json')); // Set the POST arguments to pass on curl_setopt($curl,CURLOPT_POSTFIELDS,json_encode($args)); // Make the REST call,returning the result $response = curl_exec($curl); // Close the connection curl_close( $curl ); 并且在重新生成密钥后它给我无效的api密钥仍然我得到相同的错误. 解决方法
将$args变量传递给CURLOPT_POSTFIELDS setopt调用时,不要对其进行JSON编码.
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