php – Codeigniter 2.2 – 使用左连接和多个where子句的Active

发布时间：2020-12-13 16:56:44 所属栏目：PHP教程来源：网络整理

导读：我有以下SQL： UPDATE msh_leads mlLEFT JOIN msh_leads_disposition_log dlON ml.id = dl.lead_idSET ml.assigned_to = nullWHERE ((dl.disposition_id != 6 AND dl.disposition_id != 3) OR (dl.disposition_id IS NULL))AND (ml.assigned_to = ? AND ml.d

我有以下SQL：

UPDATE msh_leads ml
LEFT JOIN msh_leads_disposition_log dl
ON ml.id = dl.lead_id
SET ml.assigned_to = null
WHERE ((dl.disposition_id != 6 AND dl.disposition_id != 3) OR (dl.disposition_id IS NULL))
AND (ml.assigned_to = ? AND ml.decline = 0 AND ml.subcategory_id = ?)

创建它有一些逻辑(根据某些情况,某些地方来来去去)所以我希望在Codeigniter(2.2)Active Record中重新创建它.我不知道如何将连接添加到更新或如何将更复杂的where语句添加到更新.

解决方法

这对你有所帮助.试试这个.

Note: you need to place your values over ? else it’ll throw an error 1064

$this->db->set('ml.assigned_to','null');
$this->db->where('ml.assigned_to = ?');
$this->db->where('((dl.disposition_id != 6 AND dl.disposition_id != 3) OR (dl.disposition_id IS NULL))');
$this->db->where('ml.decline = 0');
$this->db->where('ml.subcategory_id = ?');
$this->db->update('msh_leads ml join msh_leads_disposition_log dl on ml.id = dl.lead_id');

（编辑：李大同）

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